0

我想知道如何解析 SOAP 的输出。我当前的代码如下：

try{
    SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
    SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
    envelope.setOutputSoapObject(request);
    HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
    androidHttpTransport.call(SOAP_ACTION, envelope);

    Object response = (Object) envelope.getResponse();   

    Log.e("Output:", response.toString());

}catch (Exception e){
    Log.e("Error:", e.getCause().toString());
}

响应的输出是这样的：

[{"category_id":767,"parent_id":663,"name":"Walk"}, {"category_id":768,"parent_id":767,"name":"Google"}, {"category_id": 764,"parent_id":697,"name":"黄色"}]

那么，如何分别获取这些值呢？

我只是想让你知道，如果我改变这一行：

Object response = (Object) envelope.getResponse();

对此：

SoapObject response = (SoapObject) envelope.getResponse();

我收到以下错误：

10-01 11:28:08.086: E/AndroidRuntime(4600): FATAL EXCEPTION: main 
10-01 11:28:08.086: E/AndroidRuntime(4600): java.lang.RuntimeException: Unable to start activity ComponentInfo{com.example.WebExample/com.example.WebExample.SyncActivity}: java.lang.NullPointerException 
10-01 11:28:08.086: E/AndroidRuntime(4600):     at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:2211)
10-01 11:28:08.086: E/AndroidRuntime(4600):     at android.app.ActivityThread.handleLaunchActivity(ActivityThread.java:2261)
10-01 11:28:08.086: E/AndroidRuntime(4600):     at android.app.ActivityThread.access$600(ActivityThread.java:141) 
10-01 11:28:08.086: E/AndroidRuntime(4600):     at android.app.ActivityThread$H.handleMessage(ActivityThread.java:1256) 
10-01 11:28:08.086: E/AndroidRuntime(4600):     at android.os.Handler.dispatchMessage(Handler.java:99) 
10-01 11:28:08.086: E/AndroidRuntime(4600):     at android.os.Looper.loop(Looper.java:137) 
10-01 11:28:08.086: E/AndroidRuntime(4600):     at android.app.ActivityThread.main(ActivityThread.java:5103)
10-01 11:28:08.086: E/AndroidRuntime(4600):     at java.lang.reflect.Method.invokeNative(Native Method)
10-01 11:28:08.086: E/AndroidRuntime(4600):     at java.lang.reflect.Method.invoke(Method.java:525) 
10-01 11:28:08.086: E/AndroidRuntime(4600):     at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:737) 
10-01 11:28:08.086: E/AndroidRuntime(4600):     at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:553) 
10-01 11:28:08.086: E/AndroidRuntime(4600):     at dalvik.system.NativeStart.main(Native Method) 
10-01 11:28:08.086: E/AndroidRuntime(4600): Caused by: java.lang.NullPointerException 
10-01 11:28:08.086: E/AndroidRuntime(4600):     at 
com.example.WebExample.SyncActivity.onCreate(SyncActivity.java:49)
10-01 11:28:08.086: E/AndroidRuntime(4600):     at android.app.Activity.performCreate(Activity.java:5133)
10-01 11:28:08.086: E/AndroidRuntime(4600):     at android.app.Instrumentation.callActivityOnCreate(Instrumentation.java:1087) 
10-01 11:28:08.086: E/AndroidRuntime(4600):     at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:2175)
10-01 11:28:08.086: E/AndroidRuntime(4600):     ... 11 more

谢谢。

4

2 回答 2

1

根据您的评论，您需要解析 json 数组。

 JSONArray jr = new JSONArray("jsonstring");
 for(int i =0 ; i< jr.length();i++)
 {
 JSONObject jb =(JSONObject) jr.get(i);  
 String categoryid = jb.getString("category_id");
 String parent_id = jb.getString("parent_id");
 String name = jb.getString("name");
 }
于 2013-10-01T16:02:50.747 回答
0

感谢@Raghunandan解决。此外，它检索正确的编码，这很棒，因为 json_encode 将特殊字符放在字符串上。

try{
    SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
    SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
    envelope.setOutputSoapObject(request);
    HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
    androidHttpTransport.call(SOAP_ACTION, envelope);

    SoapObject rep = (SoapObject) envelope.bodyIn;

    JSONArray jr = new JSONArray(rep.getPropertyAsString(0));
    for(int i =0 ; i< jr.length();i++)
     {
         JSONObject jb =(JSONObject) jr.get(i);  

         String name = jb.getString("name");
         Log.e("value:", name);
     }

}catch (Exception e){
    Log.e("Error:", e.toString());
}
于 2013-10-01T16:12:27.347 回答