17

这是我的代码：

driver.findElement(By.id("ImageButton5")).click();
//Thread.sleep(3000);
String winHandleBefore = driver.getWindowHandle();
driver.switchTo().window(winHandleBefore);
driver.findElement(By.id("txtEnterCptCode")).sendKeys("99219");

现在我有下一个错误：

线程“主”org.openqa.selenium.NoSuchElementException 中的异常：无法找到 id == txtEnterCptCode 的元素（警告：服务器未提供任何堆栈跟踪信息）命令持续时间或超时：404 毫秒。

有任何想法吗？

4

6 回答 6

41

看起来您实际上并没有切换到任何新窗口。您应该获取原始窗口的窗口句柄，保存它，然后获取新窗口的窗口句柄并切换到该窗口句柄。完成新窗口后，您需要将其关闭，然后切换回原始窗口句柄。请参阅下面的示例：

IE

String parentHandle = driver.getWindowHandle(); // get the current window handle
driver.findElement(By.xpath("//*[@id='someXpath']")).click(); // click some link that opens a new window

for (String winHandle : driver.getWindowHandles()) {
    driver.switchTo().window(winHandle); // switch focus of WebDriver to the next found window handle (that's your newly opened window)
}

//code to do something on new window

driver.close(); // close newly opened window when done with it
driver.switchTo().window(parentHandle); // switch back to the original window
于 2013-10-01T12:20:25.883 回答
2

我有一个实用方法来切换到所需的窗口，如下所示

public class Utility 
{
    public static WebDriver getHandleToWindow(String title){

        //parentWindowHandle = WebDriverInitialize.getDriver().getWindowHandle(); // save the current window handle.
        WebDriver popup = null;
        Set<String> windowIterator = WebDriverInitialize.getDriver().getWindowHandles();
        System.err.println("No of windows :  " + windowIterator.size());
        for (String s : windowIterator) {
          String windowHandle = s; 
          popup = WebDriverInitialize.getDriver().switchTo().window(windowHandle);
          System.out.println("Window Title : " + popup.getTitle());
          System.out.println("Window Url : " + popup.getCurrentUrl());
          if (popup.getTitle().equals(title) ){
              System.out.println("Selected Window Title : " + popup.getTitle());
              return popup;
          }

        }
                System.out.println("Window Title :" + popup.getTitle());
                System.out.println();
            return popup;
        }
}

一旦窗口的标题作为参数传递，它将带您到所需的窗口。在你的情况下，你可以做到。

Webdriver childDriver = Utility.getHandleToWindow("titleOfChildWindow");

然后再次使用相同的方法切换到父窗口

Webdriver parentDriver = Utility.getHandleToWindow("titleOfParentWindow");

此方法在处理多个窗口时有效。

于 2013-10-01T09:50:18.250 回答
1 
Set<String> windows = driver.getWindowHandles();
Iterator<String> itr = windows.iterator();

//patName will provide you parent window
String patName = itr.next();

//chldName will provide you child window
String chldName = itr.next();

//Switch to child window
driver.switchto().window(chldName);

//Do normal selenium code for performing action in child window

//To come back to parent window
driver.switchto().window(patName);
于 2014-11-11T07:40:13.543 回答
0

我有一个示例程序：

公共类 BrowserBackForward {

/**
 * @param args
 * @throws InterruptedException 
 */
public static void main(String[] args) throws InterruptedException {
    WebDriver driver = new FirefoxDriver();
    driver.get("http://seleniumhq.org/");
    driver.manage().timeouts().implicitlyWait(10, TimeUnit.SECONDS);
    //maximize the window
    driver.manage().window().maximize();

    driver.findElement(By.linkText("Documentation")).click();
    System.out.println(driver.getCurrentUrl());
    driver.navigate().back();
    System.out.println(driver.getCurrentUrl());
    Thread.sleep(30000);
    driver.navigate().forward();
    System.out.println("Forward");
    Thread.sleep(30000);
    driver.navigate().refresh();

}

}

于 2013-10-01T12:21:08.900 回答
0 
                string BaseWindow = driver.CurrentWindowHandle;
                ReadOnlyCollection<string> handles = driver.WindowHandles;
                foreach (string handle in handles)
                {
                    if (handle != BaseWindow)
                    {
                        string title = driver.SwitchTo().Window(handle).Title;
                        Thread.Sleep(3000);
                        driver.SwitchTo().Window(handle).Title.Equals(title);
                        Thread.Sleep(3000);
                    }
                }
于 2014-03-12T10:28:11.343 回答
0

我在使用 windowhandle 时遇到了一些问题并尝试了这个。这个对我有用。

String parentWindowHandler = driver.getWindowHandle(); 
String subWindowHandler = null;

Set<String> handles = driver.getWindowHandles();
Iterator<String> iterator = handles.iterator();
while (iterator.hasNext()){
    subWindowHandler = iterator.next();
    driver.switchTo().window(subWindowHandler);

    System.out.println(subWindowHandler);
}


driver.switchTo().window(parentWindowHandler);
于 2017-06-07T23:42:39.067 回答