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我对 c++ 很陌生，这里有很多代码，所以我会尽力将它浓缩到问题区域。当我尝试使用 getline 获取用户输入时，我收到此错误。因为我不希望文件名中有空格（我制作了文件），所以我使用 cin << 效果很好，但是在尝试读取文件时遇到了同样的错误。代码如下

// includes here

using namespace std;

//other prototypes here
string getUserDataFromFile(vector<int>&, int&, string);


int main()
{
    vector<int> numbers;
    numbers.reserve(50);
    int numberOfElements = 0;
    int number = 0;
    int numToFind = 0;
    int numberPosition = -1;
    int useFile = 0;
    string filename = "";
    string fileReadMessage = "";
    string output = "";
    string outFilename = "";


    cout << "Would you like to load the data from a file?(1 for yes 0 for no)";
    cin >> useFile;
    cin.ignore(INT_MAX, '\n');
    //get user data for manual input
    if(useFile == 0)
    {
        //code here for manual input(works fine)...
    }
    //get userdata for file input
    else
    {
        cout << "Please Enter the file path to be opened" << endl;

        //fixed after adding cin.ignore(INT_MAX, '\n'); 
        //see next function for another problem
        getline(cin, filename);

        fileReadMessage = getUserDataFromFile(numbers, numToFind, filename);
    }

    //some code to get data for output


    return 0;
}




//function to get user data from file
//@param v(vector<int>&) - vector of integers.
//@param numToFind(int&) - the number we are looking for
//@param filename(string) - the filename of the file with data
//@return message(string) - a message containing errors or success.
string getUserDataFromFile(vector<int>& v, int& numToFind, string filename)
{
    string message = "File Accepted";
    string line = "";
    int numOfElements = 0;
    int count = 0;

    ifstream fileToRead(filename.c_str());

    //using 'cin >>' in main, the program runs till here then breaks

    //if message is a file, extract message from file
    if (fileToRead.is_open())
    {
        while (getline(fileToRead,line))
        {
            //code to do stuff with file contents here
        }
        fileToRead.close();
    }
    else
    {
        message = "Unable to open file.";
    }
    return message;
}

我在问题区域留下了一些评论，并遗漏了大部分我没有遇到问题或无法测试的代码。任何帮助表示赞赏。谢谢！

所以我的第一个问题是通过添加 cin.ignore(INT_MAX, '\n'); 对下一个问题有任何猜测吗？它是下一个函数中的 if (fileToRead.is_open()) 行

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1 回答 1

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添加

cin.ignore();

前：

getline(cin, filename);

否则，您在输入后键入的 ENTERuseFile将被读入filename.

于 2013-10-01T06:12:03.297 回答