102

我正在使用 Xcode 5 的资产目录,我想使用我LaunchImage的作为我的主视图的背景图像(一种非常常见的做法,可以使从“加载”到“加载”的过渡看起来平滑)。

我想在资产目录中使用相同的条目来节省空间,而不必在两个不同的图像集中复制图像。

但是,调用:

UIImage *image = [UIImage imageNamed:@"LaunchImage"]; //returns nil
4

14 回答 14

83

这是 LaunchImage 的(几乎)完整列表(不包括没有状态栏的 iPad 图像):

  • LaunchImage-568h@2x.png
  • LaunchImage-700-568h@2x.png
  • LaunchImage-700-Landscape@2x~ipad.png
  • LaunchImage-700-Landscape~ipad.png
  • LaunchImage-700-Portrait@2x~ipad.png
  • LaunchImage-700-Portrait~ipad.png
  • LaunchImage-700@2x.png
  • LaunchImage-Landscape@2x~ipad.png
  • LaunchImage-横向~ipad.png
  • LaunchImage-Portrait@2x~ipad.png
  • LaunchImage-Portrait~ipad.png
  • 启动图像.png
  • LaunchImage@2x.png
  • LaunchImage-800-667h@2x.png (iPhone 6)
  • LaunchImage-800-Portrait-736h@3x.png (iPhone 6 Plus 纵向)
  • LaunchImage-800-Landscape-736h@3x.png(iPhone 6 Plus 横向)
  • LaunchImage-1100-Portrait-2436h@3x.png (iPhone X 纵向)
  • LaunchImage-1100-Landscape-2436h@3x.png(iPhone X 横向)
于 2013-11-18T10:11:27.287 回答
67
- (NSString *)splashImageNameForOrientation:(UIInterfaceOrientation)orientation {
    CGSize viewSize = self.view.bounds.size;
    NSString* viewOrientation = @"Portrait";
    if (UIDeviceOrientationIsLandscape(orientation)) {
        viewSize = CGSizeMake(viewSize.height, viewSize.width);
        viewOrientation = @"Landscape";
    }

    NSArray* imagesDict = [[[NSBundle mainBundle] infoDictionary] valueForKey:@"UILaunchImages"];
    for (NSDictionary* dict in imagesDict) {
        CGSize imageSize = CGSizeFromString(dict[@"UILaunchImageSize"]);
        if (CGSizeEqualToSize(imageSize, viewSize) && [viewOrientation isEqualToString:dict[@"UILaunchImageOrientation"]])
            return dict[@"UILaunchImageName"];
    }
    return nil;
}
于 2015-01-06T11:43:28.790 回答
52

The LaunchImages are special, and aren't actually an asset catalog on the device. If you look using iFunBox/iExplorer/etc (or on the simulator, or in the build directory) you can see the final names, and then write code to use them - eg. for an iOS7-only iPhone-only project, this will set the right launch image:

NSString *launchImage;
if  ((UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone) &&
     ([UIScreen mainScreen].bounds.size.height > 480.0f)) {
    launchImage = @"LaunchImage-700-568h";
} else {
    launchImage = @"LaunchImage-700";
}

[self.launchImageView setImage:[UIImage imageNamed:launchImage]];

I put this into viewDidLoad.

This isn't really ideal, it would be great if Apple would give us a nice API to do this.

于 2013-10-09T16:05:15.240 回答
27

我的应用目前仅支持 iOS 7 及更高版本。

这就是我从资产目录中引用启动图像的方式:

NSDictionary *dict = @{@"320x480" : @"LaunchImage-700",
                       @"320x568" : @"LaunchImage-700-568h",
                       @"375x667" : @"LaunchImage-800-667h",
                       @"414x736" : @"LaunchImage-800-Portrait-736h"};
NSString *key = [NSString stringWithFormat:@"%dx%d",
    (int)[UIScreen mainScreen].bounds.size.width,
    (int)[UIScreen mainScreen].bounds.size.height];
UIImage *launchImage = [UIImage imageNamed:dict[key]];

如果你想支持旧的 iOS 版本,你可以添加更多的键值对。

于 2014-09-15T21:05:21.820 回答
10

这是基于上面 Cherpak Evgeny 提供的解决方案的 UIImage 类别。

UIImage+SplashImage.h

#import <UIKit/UIKit.h>

/**
 * Category on `UIImage` to access the splash image.
 **/
@interface UIImage (SplashImage)

/**
 * Return the name of the splash image for a given orientation.
 * @param orientation The interface orientation.
 * @return The name of the splash image.
 **/
+ (NSString *)si_splashImageNameForOrientation:(UIInterfaceOrientation)orientation;

/**
 * Returns the splash image for a given orientation.
 * @param orientation The interface orientation.
 * @return The splash image.
 **/
+ (UIImage*)si_splashImageForOrientation:(UIInterfaceOrientation)orientation;

@end

UIImage+SplashImage.m

#import "UIImage+SplashImage.h"

@implementation UIImage (SplashImage)

+ (NSString *)si_splashImageNameForOrientation:(UIInterfaceOrientation)orientation
{
    CGSize viewSize = [UIScreen mainScreen].bounds.size;

    NSString *viewOrientation = @"Portrait";

    if (UIDeviceOrientationIsLandscape(orientation))
    {
        viewSize = CGSizeMake(viewSize.height, viewSize.width);
        viewOrientation = @"Landscape";
    }

    NSArray* imagesDict = [[[NSBundle mainBundle] infoDictionary] valueForKey:@"UILaunchImages"];

    for (NSDictionary *dict in imagesDict)
    {
        CGSize imageSize = CGSizeFromString(dict[@"UILaunchImageSize"]);
        if (CGSizeEqualToSize(imageSize, viewSize) && [viewOrientation isEqualToString:dict[@"UILaunchImageOrientation"]])
            return dict[@"UILaunchImageName"];
    }
    return nil;
}

+ (UIImage*)si_splashImageForOrientation:(UIInterfaceOrientation)orientation
{
    NSString *imageName = [self si_splashImageNameForOrientation:orientation];
    UIImage *image = [UIImage imageNamed:imageName];
    return image;
}

@end
于 2015-01-22T17:16:45.167 回答
9

@codeman 为 Swift 1.2 更新的答案:

func splashImageForOrientation(orientation: UIInterfaceOrientation, size: CGSize) -> String? {
    var viewSize        = size
    var viewOrientation = "Portrait"

    if UIInterfaceOrientationIsLandscape(orientation) {
        viewSize        = CGSizeMake(size.height, size.width)
        viewOrientation = "Landscape"
    }

    if let imagesDict = NSBundle.mainBundle().infoDictionary as? [String: AnyObject] {
        if let imagesArray = imagesDict["UILaunchImages"] as? [[String: String]] {
            for dict in imagesArray {
                if let sizeString = dict["UILaunchImageSize"], let imageOrientation = dict["UILaunchImageOrientation"] {
                    let imageSize = CGSizeFromString(sizeString)
                    if CGSizeEqualToSize(imageSize, viewSize) && viewOrientation == imageOrientation {
                        if let imageName = dict["UILaunchImageName"] {
                            return imageName
                        }
                    }
                }
            }
        }
    }

    return nil

}

调用它并支持 iOS 8 的旋转:

override func viewWillAppear(animated: Bool) {
    if let img = splashImageForOrientation(UIApplication.sharedApplication().statusBarOrientation, size: self.view.bounds.size) {
        backgroundImage.image = UIImage(named: img)
    }
}

override func viewWillTransitionToSize(size: CGSize, withTransitionCoordinator coordinator: UIViewControllerTransitionCoordinator) {
    let orientation = size.height > size.width ? UIInterfaceOrientation.Portrait : UIInterfaceOrientation.LandscapeLeft

    if let img = splashImageForOrientation(orientation, size: size) {
        backgroundImage.image = UIImage(named: img)
    }

}

正是我需要的,谢谢!

于 2015-04-22T09:08:26.287 回答
7

我刚刚写了一个通用方法来获取 iPhone 和 iPad 的启动图像名称(横向、纵向),它对我有用,希望它也能帮助你。我在其他 SO 答案的帮助下写了这个,感谢@Pichirichi 的整个列表。

+(NSString*)getLaunchImageName
{

 NSArray* images= @[@"LaunchImage.png", @"LaunchImage@2x.png",@"LaunchImage-700@2x.png",@"LaunchImage-568h@2x.png",@"LaunchImage-700-568h@2x.png",@"LaunchImage-700-Portrait@2x~ipad.png",@"LaunchImage-Portrait@2x~ipad.png",@"LaunchImage-700-Portrait~ipad.png",@"LaunchImage-Portrait~ipad.png",@"LaunchImage-Landscape@2x~ipad.png",@"LaunchImage-700-Landscape@2x~ipad.png",@"LaunchImage-Landscape~ipad.png",@"LaunchImage-700-Landscape~ipad.png"];

UIImage *splashImage;

if ([self isDeviceiPhone])
{
    if ([self isDeviceiPhone4] && [self isDeviceRetina])
    {
        splashImage = [UIImage imageNamed:images[1]];
        if (splashImage.size.width!=0)
            return images[1];
        else
            return images[2];
    }
    else if ([self isDeviceiPhone5])
    {
        splashImage = [UIImage imageNamed:images[1]];
        if (splashImage.size.width!=0)
            return images[3];
        else
            return images[4];
    }
    else
        return images[0]; //Non-retina iPhone
}
else if ([[UIDevice currentDevice] orientation]==UIDeviceOrientationPortrait || [[UIDevice currentDevice] orientation] == UIDeviceOrientationPortraitUpsideDown)//iPad Portrait
{
    if ([self isDeviceRetina])
    {
        splashImage = [UIImage imageNamed:images[5]];
        if (splashImage.size.width!=0)
            return images[5];
        else
            return images[6];
    }
    else
    {
        splashImage = [UIImage imageNamed:images[7]];
        if (splashImage.size.width!=0)
            return images[7];
        else
            return images[8];
    }

}
else
{
    if ([self isDeviceRetina])
    {
        splashImage = [UIImage imageNamed:images[9]];
        if (splashImage.size.width!=0)
            return images[9];
        else
            return images[10];
    }
    else
    {
        splashImage = [UIImage imageNamed:images[11]];
        if (splashImage.size.width!=0)
            return images[11];
        else
            return images[12];
    }
 }
}

其他实用方法是

+(BOOL)isDeviceiPhone
{
 if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone)
 {
     return TRUE;
 }

 return FALSE;
}

+(BOOL)isDeviceiPhone4
{
 if ([[UIScreen mainScreen] bounds].size.height==480)
    return TRUE;

 return FALSE;
}


+(BOOL)isDeviceRetina
{
 if ([[UIScreen mainScreen] respondsToSelector:@selector(displayLinkWithTarget:selector:)] &&
    ([UIScreen mainScreen].scale == 2.0))        // Retina display
 {
    return TRUE;
 } 
 else                                          // non-Retina display
 {
     return FALSE;
 }
}


+(BOOL)isDeviceiPhone5
{
 if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone && [[UIScreen mainScreen] bounds].size.height>480)
 {
    return TRUE;
 }
 return FALSE;
}
于 2014-04-30T06:09:03.737 回答
7

Cherpak Evgeny 回答的 Swift 版本:

    func splashImageForOrientation(orientation: UIInterfaceOrientation) -> String {
        var viewSize = self.view.bounds.size
        var viewOrientation = "Portrait"
        if UIInterfaceOrientationIsLandscape(orientation) {
           viewSize = CGSizeMake(viewSize.height, viewSize.width)
           viewOrientation = "Landscape"
        }
        let imagesDict = NSBundle.mainBundle().infoDictionary as Dictionary<NSObject,AnyObject>!
        let imagesArray = imagesDict["UILaunchImages"] as NSArray
        for dict in imagesArray {
            let dictNSDict = dict as NSDictionary
            let imageSize = CGSizeFromString(dictNSDict["UILaunchImageSize"] as String)
            if CGSizeEqualToSize(imageSize, viewSize) && viewOrientation == (dictNSDict["UILaunchImageOrientation"] as String) {
                return dictNSDict["UILaunchImageName"] as String
            }
        }
        return ""
    }
于 2015-02-19T19:56:36.903 回答
5

在@Pichirich 的回答之后,我在 InterfaceBuilder 中引用了我的启动图像:

“启动图像.png”

...在 Xcode 5.0.2 中,它会自动从资产目录中直接提取适当的图像。

这是我所期望的——除了苹果公司将“Default.png”静默重命名为“LaunchImage.png”的恶毒举动:)

于 2013-11-20T12:40:00.300 回答
3

只需一行代码即可轻松访问 Launch 图像。

 UIImage *myAppsLaunchImage = [UIImage launchImage];

请按照下面给出的步骤来实现上述功能。

步骤 1.UIImage通过创建类别来扩展

+ (UIImage *)launchImage {
    NSDictionary *dOfLaunchImage = [NSDictionary dictionaryWithObjectsAndKeys:
                                    @"LaunchImage-568h@2x.png",@"568,320,2,8,p", // ios 8 - iphone 5 - portrait
                                    @"LaunchImage-568h@2x.png",@"568,320,2,8,l", // ios 8 - iphone 5 - landscape
                                    @"LaunchImage-700-568h@2x.png",@"568,320,2,7,p", // ios 7 - iphone 5 - portrait
                                    @"LaunchImage-700-568h@2x.png",@"568,320,2,7,l", // ios 7 - iphone 5 - landscape
                                    @"LaunchImage-700-Landscape@2x~ipad.png",@"1024,768,2,7,l", // ios 7 - ipad retina - landscape
                                    @"LaunchImage-700-Landscape~ipad.png",@"1024,768,1,7,l", // ios 7 - ipad regular - landscape
                                    @"LaunchImage-700-Portrait@2x~ipad.png",@"1024,768,2,7,p", // ios 7 - ipad retina - portrait
                                    @"LaunchImage-700-Portrait~ipad.png",@"1024,768,1,7,p", // ios 7 - ipad regular - portrait
                                    @"LaunchImage-700@2x.png",@"480,320,2,7,p", // ios 7 - iphone 4/4s retina - portrait
                                    @"LaunchImage-700@2x.png",@"480,320,2,7,l", // ios 7 - iphone 4/4s retina - landscape
                                    @"LaunchImage-Landscape@2x~ipad.png",@"1024,768,2,8,l", // ios 8 - ipad retina - landscape
                                    @"LaunchImage-Landscape~ipad.png",@"1024,768,1,8,l", // ios 8 - ipad regular - landscape
                                    @"LaunchImage-Portrait@2x~ipad.png",@"1024,768,2,8,p", // ios 8 - ipad retina - portrait
                                    @"LaunchImage-Portrait~ipad.png",@"1024,768,1,8,l", // ios 8 - ipad regular - portrait
                                    @"LaunchImage.png",@"480,320,1,7,p", // ios 6 - iphone 3g/3gs - portrait
                                    @"LaunchImage.png",@"480,320,1,7,l", // ios 6 - iphone 3g/3gs - landscape
                                    @"LaunchImage@2x.png",@"480,320,2,8,p", // ios 6,7,8 - iphone 4/4s - portrait
                                    @"LaunchImage@2x.png",@"480,320,2,8,l", // ios 6,7,8 - iphone 4/4s - landscape
                                    @"LaunchImage-800-667h@2x.png",@"667,375,2,8,p", // ios 8 - iphone 6 - portrait
                                    @"LaunchImage-800-667h@2x.png",@"667,375,2,8,l", // ios 8 - iphone 6 - landscape
                                    @"LaunchImage-800-Portrait-736h@3x.png",@"736,414,3,8,p", // ios 8 - iphone 6 plus - portrait
                                    @"LaunchImage-800-Landscape-736h@3x.png",@"736,414,3,8,l", // ios 8 - iphone 6 plus - landscape
                                    nil];
    NSInteger width = ([UIScreen mainScreen].bounds.size.width>[UIScreen mainScreen].bounds.size.height)?[UIScreen mainScreen].bounds.size.width:[UIScreen mainScreen].bounds.size.height;
    NSInteger height = ([UIScreen mainScreen].bounds.size.width>[UIScreen mainScreen].bounds.size.height)?[UIScreen mainScreen].bounds.size.height:[UIScreen mainScreen].bounds.size.width;
    NSInteger os = [[[[[UIDevice currentDevice] systemVersion] componentsSeparatedByString:@"."] objectAtIndex:0] integerValue];
    NSString *strOrientation = UIDeviceOrientationIsLandscape([[UIDevice currentDevice] orientation])?@"l":@"p";
    NSString *strImageName = [NSString stringWithFormat:@"%li,%li,%li,%li,%@",width,height,(NSInteger)[UIScreen mainScreen].scale,os,strOrientation];
    UIImage *imageToReturn = [UIImage imageNamed:[dOfLaunchImage valueForKey:strImageName]];
    if([strOrientation isEqualToString:@"l"] && [strImageName rangeOfString:@"Landscape"].length==0) {
        imageToReturn = [UIImage rotate:imageToReturn orientation:UIImageOrientationRight];
    }
    return imageToReturn;
}

第 2 步。上述方法应该通过将以下代码也添加到同一类别中来工作UIImage

static inline double radians (double degrees) {return degrees * M_PI/180;}

+ (UIImage *)rotate:(UIImage*)src orientation:(UIImageOrientation) orientation {
    UIGraphicsBeginImageContext(src.size);
    CGContextRef context = UIGraphicsGetCurrentContext();
    if (orientation == UIImageOrientationRight) {
        CGContextRotateCTM (context, radians(90));
    } else if (orientation == UIImageOrientationLeft) {
        CGContextRotateCTM (context, radians(-90));
    } else if (orientation == UIImageOrientationDown) {
        // NOTHING
    } else if (orientation == UIImageOrientationUp) {
        CGContextRotateCTM (context, radians(90));
    }
    [src drawAtPoint:CGPointMake(0, 0)];
    UIImage *image = UIGraphicsGetImageFromCurrentImageContext();
    UIGraphicsEndImageContext();
    return image;
}
于 2014-11-21T11:12:19.963 回答
3

文档中有明确说明:

“资产目录中的每个集合都有一个名称您可以使用该名称以编程方式加载集合中包含的任何单个图像。要加载图像,请调用UIImage:ImageNamed:方法,传递包含图像的集合的名称。”

使用 Pichirich 的列表有助于解决这种不一致。

于 2014-04-25T18:56:34.800 回答
2

我意识到这不一定是每个人的最佳解决方案,但最简单(且最不容易出错,恕我直言)的方法是在您的 Images.xcassets 目录中创建一个单独的条目。我叫它SplashImage

当您添加新条目时,请确保不要选择“新启动图像”作为选项。相反,选择通用的“新图像集”。接下来,打开检查器并选择相关选项。如果您只为视网膜设备构建,就像我一样,您可以选择以下内容:

图像检查器

这将为您留下四个条目(iPhone 4S、iPhone 5(s,c)、iPhone 6 和 iPhone 6 Plus)。

图片

图片对应的文件如下:

| Resolution (Xcode entry) | Launch Image name   |   Device         |
|--------------------------|---------------------|------------------|
| 1x                       | Default-750.png     | iPhone 6         |
| 2x                       | Default@2x.png      | iPhone 4S        |
| Retina 4 2x              | Default-568h@2x.png | iPhone 5, 5s, 5c |
| 3x                       | Default-1242.png    | iPhone 6 Plus    |

当然,完成此操作后,您可以简单地使用[UIImage imageNamed:@"SplashImage"]

于 2014-09-11T18:07:10.643 回答
2

在 Pichirich 的回答的帮助下,我实现了以下类别(iOS 7+): UIImage+AssetLaunchImage

它实际上只是动态生成名称,但可能会有所帮助。

于 2014-11-26T18:59:20.040 回答
0

更新到最新的 Swift 语法 (Swift 5)

   func splashImageForOrientation(orientation: UIInterfaceOrientation) -> String? {

    var viewSize = screenSize
    var viewOrientation = "Portrait"
    if orientation.isLandscape {
        viewSize = CGSize(width: viewSize.height, height: viewSize.width)
        viewOrientation = "Landscape"
    }
    if let infoDict = Bundle.main.infoDictionary, let launchImagesArray = infoDict["UILaunchImages"] as? [Any] {
        for launchImage in launchImagesArray {
            if let launchImage = launchImage as? [String: Any], let nameString = launchImage["UILaunchImageName"] as? String, let sizeString = launchImage["UILaunchImageSize"] as? String, let orientationString = launchImage["UILaunchImageOrientation"] as? String {
                let imageSize = NSCoder.cgSize(for: sizeString)
                if imageSize.equalTo(viewSize) && viewOrientation == orientationString {
                    return nameString
                }
            }
        }
    }
    return nil
}
于 2019-04-15T10:55:57.350 回答