对于在 Web 表单应用程序中超级简单的操作,我花了数小时处理许多找到的示例,但都没有成功。即上传一个或多个文件并存储在sql server中。
在网络表单(vb.net)中,我可以这样做:
Dim fs As Stream = fileUpload1.PostedFile.InputStream
Dim br As New BinaryReader(fs)
Dim bytes As Byte() = br.ReadBytes(fs.Length)
'insert the file into database
Dim strQuery As String = "INSERT INTO files ([name], [type], [file]) VALUES (@Name, @ContentType, @Data)"
Dim cmd As New SqlCommand(strQuery)
cmd.Parameters.Add("@Name", SqlDbType.VarChar).Value = filename
cmd.Parameters.Add("@ContentType", SqlDbType.VarChar).Value() = contenttype
cmd.Parameters.Add("@Data", SqlDbType.Binary).Value = bytes
然后做数据库执行语句……完成!
现在 C# Web-Api:
我现在通过 Web-Api 将上传保存到文件系统的看似不错的示例是:
public Task<IEnumerable<FileDesc>> Old()
{
string folderName = "uploads";
string PATH = HttpContext.Current.Server.MapPath("~/" + folderName);
string rootUrl = Request.RequestUri.AbsoluteUri.Replace(Request.RequestUri.AbsolutePath, String.Empty);
if (Request.Content.IsMimeMultipartContent())
{
var streamProvider = new MultipartFormDataStreamProvider(PATH);
var task = Request.Content.ReadAsMultipartAsync(streamProvider).ContinueWith<IEnumerable<FileDesc>>(t =>
{
if (t.IsFaulted || t.IsCanceled)
{
throw new HttpResponseException(HttpStatusCode.InternalServerError);
}
var fileInfo = streamProvider.FileData.Select(i =>
{
var info = new FileInfo(i.LocalFileName);
return new FileDesc(info.Name, rootUrl + "/" + folderName + "/" + info.Name, info.Length / 1024);
});
return fileInfo;
});
return task;
}
else
{
throw new HttpResponseException(Request.CreateResponse(HttpStatusCode.NotAcceptable, "This request is not properly formatted"));
}
}
我似乎无法弄清楚如何获取每个多部分文件内容流,以便我可以发送到数据库。我看过有关 MultipartMemoryStreamProvider 和 MultipartStreamProvider 的帖子,但我还没有弄清楚如何使用它们。作为一个 C# 和 Web-Api 的新手,我显然已经不知所措了。
谁能指导我如何将文件内容放入流中,我可以将字节发送到数据库?