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我想知道使用以下示例将级联陷阱归结到多远。

(defn -main
 "Good ole main boilerplate"
 [people-path trap-path output-path]
 (?- (hfs-textline output-path)
     (people-query (hfs-textline trap-path)
                   (hfs-textline people-path))))

(defn people-query
  "The people query!"
  [trap-path people-path]
  (<- [?first-name ?last-name ?daily-visits]
      (:trap trap)
      (some-generic-parsing-to-tuple-fn people-path :> ?fname ?lname)
      (c/count ?daily-visits)))

如果some-generic-parsing-to-tuple-fn在人员查询的范围内调用（其中包含(:trap trap)子查询是否也可以访问该陷阱，或者是否some-generic-parsing-to-tuple-fn还应该包含陷阱信息，即

 (some-generic-parsing-to-tuple-fn trap-path people-path :> ?fname ?lname)

TL;DR 我需要在 Cascalog 查询中传递多少陷阱才能允许嵌套查询访问陷阱

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