I am a python beginner . I was trying to run this code :
def main():
print ( " This program computes the average of two exam scores . ")
score1,score2 = input ("Enter two scores separated by a comma:")
average = (score1 + score2)/2.0
print ("The average of the score is : " , average )
when I summon the main() I got this ValueError :
ValueError: too many values to unpack (expected 2)
what is wrong with this code ?
score1 + score2将执行字符串添加，否则您将收到错误消息。你需要用逗号分开：
score1,score2 = input ("Enter two scores separated by a comma:").split(",")
但是请注意，score1andscore2仍然是字符串。您需要使用float或int（取决于您想要的数字类型）将它们转换为数字。
看一个例子：
>>> score1,score2 = input("Enter two scores separated by a comma:").split(",")
Enter two scores separated by a comma:1,2
>>> score1
'1'
>>> score1 = int(score1)
>>> score1
1
>>> score1 = float(score1)
>>> score1
1.0
>>>
输入作为单个字符串到达。但是 Python 在字符串方面有一个分裂的个性：它可以将它们视为单个字符串值，或作为字符列表。当您尝试将其分配给它时score1,score2，决定您想要一个字符列表。显然你输入了两个以上的字符，所以它说你有太多了。
其他答案对做你真正想做的事情有很好的建议，所以我不会在这里重复。
如果您使用 args 并在运行文件时给出较少的值，它将向您显示此错误。
**纠正给出正确的值**
from sys import argv
one, two, three,four,five = argv
c=input("Enter the coffee you need?: ")
print("File Name is ",one)
print("First you need ",two)
print("The you need",three)
print("Last you need",four)
print("Last but not least you need",five)
print(f"you need above mentioned items to make {c}.")
While running code give it like this: **python hm5.py milk coffeepowder sugar water**
milk == two
coffeepowder ==three
sugar == four
water == five
one == file name (you don't need to give it while running
My output:
Enter the coffee you need?: filter coffee
First you need milk
The you need coffeepowder
Last you need sugar
Last but not least you need water
you need above mentioned items to make filter coffee.
>>>number1,number2 = input("enter numbers: ").split(",")
enter numbers: 1,2
>>> number1
'1'
>>> number2
'2'
然后你可以转换成整数
>>> number1 = int(number1)
>>> number2 = int(number2)
>>> average = (number1+number2)/2.0
>>> average
1.5