我发现格式运算符在函数内部的工作方式与普通脚本不同。这是一个按预期工作的简单示例：
[string]$name = 'Scripting Guy'
[string]$statement = 'PowerShell rocks'
$s = "The {0} thinks that {1}!" -f $name, $statement
write-host $s
生产：
The Scripting Guy thinks that PowerShell rocks!
在函数内部时，它会做一些不同的事情：
function myFunc( [string] $iname, [string] $istatement) {
$s = "The {0} thinks that {1}!" -f $iname, $istatement
write-host $s
}
[string]$name = 'Scripting Guy'
[string]$statement = 'PowerShell rocks'
myFunc($name, $statement)
产生：
The Scripting Guy PowerShell rocks thinks that !
我试图玩弄它以了解它在做什么：
function myFunc( [string] $iname, [string] $istatement) {
$s = "The {0} thinks that {1}! {2} {3}" -f $iname, $istatement, "=====", $iname
write-host $s
}
[string]$name = 'Scripting Guy'
[string]$statement = 'PowerShell rocks'
myFunc($name, $statement)
这会产生：
The Scripting Guy PowerShell rocks thinks that ! ===== Scripting Guy PowerShell rocks
所以现在我不知道该怎么想。