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我的应用程序中有很长的单选按钮列表。

如何删除文本不包含字符串“test”的所有按钮?

4

3 回答 3

1

如果您将它们放在像 List 这样的列表中,那将非常简单。

List<RadioButton> testButtons = new ArrayList<RadioButton>();
for (RadioButton button: radioButtonList) {
    if (button.getText().toString().contains("test")) {
         testButtons.add(button);
    }
}

// assuming that they all have the same parent view
View parentView = findViewById(R.id.parentView);
for (RadioButton testButton: testButtons ) {
    parentView.removeView(button)
    // or as Evan B suggest, which is even simpler (though then it is not 'removed' from the view in the litteral sense
    testButton.setVisibility(GONE); 
}
于 2013-09-30T00:08:08.460 回答
1

一键示例:

Button buttonOne = (Button) findViewById(R.id.buttonOne);

removeButtons();


public void removeButtons() {
    if (buttonOne.getText().toString() != "test") {
        buttonOne.setVisibility(GONE);
    }
}

如果您有阵列,请将其切换。

于 2013-09-30T00:11:36.237 回答
1

你可以自动化这个:

ViewGroup vg= (ViewGroup) findViewById(R.id.your_layout);

int iter=0;
while(iter<vg.getChildCount()){
 boolean found=false;
 View rb=vg.getChildAt(iter);

 if(rb instanceof RadioButton){
  if(rb.getText().toString().contains(my_string)){//found a pattern
     vg.removeView(rb);//remove RadioButton
     found=true;
  }
 }
 if(!found) ++iter;//iterate on the views of the group if the tested view is not a RadioButton; else continue to remove

}

上面的代码不处理另一个视图组内的视图组(例如,另一个视图组内的 LinearLayout)。调用removeView后,我没有测试迭代器的代码和视图组的状态;您可以在控制台中检查它并告诉我们。

于 2013-09-30T02:13:29.610 回答