只是为了在展示代码之前提供一些我正在从事的项目的背景知识。我目前正在开发一个 Python 脚本,该脚本将在 Raspberry Pi 上运行,以监控地下室污水泵的浮子开关。此代码将检查污水泵是否不符合以下两个标准:
- 如果开关打开超过三分钟
- 如果开关在三分钟内开关超过 10 次
我还没有完成其余的代码,但这是我所拥有的:
import time
import RPi.GPIO as GPIO
GPIO.setmode(GPIO.BCM)
GPIO.setup(17, GPIO.IN)
floatSwitch = GPIO.input(17)
import smtplib
running = True
log = open("sumpPumpLog.txt", "r+")
startTime = time.time()
def elapsedTime():
"""This function checks how much time
has elapsed since the timer has started"""
endtime = time.time()
elapsed = endtime - starttime
return elapsed
def sendEmail(*msg):
"""This function sends an email to selected recipients with a custom
message as well as the log file attached."""
#enter the code that sends an email to the family with the log attached
fromaddr = 'from@email.com'
toaddrs = [to@email.com']
msg = """Please see the Pi and the data log file for more details."""
# Credentials (if needed)
username = 'my_username'
password = 'my_password'
msg.attached()
# The actual mail send
server = smtplib.SMTP('smtp.gmail.com:587')
server.starttls()
server.login(username, password)
server.sendmail(fromaddr, toaddrs, msg)
server.quit()
if running is True:
if floatSwitch is True:
#Write the time and what happened to the file
log.write(str(time.time() + "Float switch turned on")
#Wait until switch is turned off
while floatSwitch is True:
startTime = time.time()
if floatSwitch is False:
log.write(str(now) + "Float switch turned off")
break
#if elapsedTime > 3 min (in the form of 180 seconds)
elif elapsedTime() > 180:
log.write(str(now) + "Sump Pump has been deemed broaken")
sendEmail("The sump pump is now broken.")
else:
log.write(str(time.time() + "The sctipt has stopped.")
sendEmail("The script has been stopped.")
我的问题是在第 52 行,当它说
while floatSwitch is True:
代码中有一个错误,它所说的只是“无效的语法”。我对 Python 很陌生,这是我第一个真正使用它的项目。我不熟悉很多语法,所以这可能是一个非常基本的错误。任何人都可以帮我修复此语句的语法,以便我可以让我的代码正常工作。我知道在没有其余代码的情况下还有许多其他错误,但我计划在找到这些错误时解决它们。我四处搜寻,但找不到另一个这样的例子。非常感谢任何和所有帮助!