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我只是想养成像素操作的习惯，它并没有改变任何东西。

我使用以下循环来反转每个像素：

var newImage = context.createImageData(canvas.width, canvas.height);
var arr = context.getImageData(0, 0, canvas.width, canvas.height);
var pixels = arr.data;

for(var i = 0; i < pixels.length; i+=4){
    var r = 255 - pixels[i];
    var g = 255 - pixels[i + 1];
    var b = 255 - pixels[i + 2];
    var a = pixels[i + 3];
    newImage.data[i] = r;
    newImage.data[i + 1] = g;
    newImage.data[i + 2] = b;
    newImage.data[i + 3] = a;
}

然而，当我尝试清除画布并重写它时，什么也没有发生：

context.clearRect(0, 0, canvas.width, canvas.height);
context.putImageData(newImage, 0, 0);

为什么这不起作用？我究竟做错了什么？

jsfiddle

4

1 回答 1

2

问题来自图像（尚未加载）。您的代码有效（观看这个没有图像的小提琴 - http://jsfiddle.net/B82nk/1/）。

你必须这样做：

var canvas = document.getElementById('canvas');
var context = canvas.getContext('2d');
canvas.width = 500;
canvas.height = 322;

var image_obj = new Image(); 
image_obj.onload = function(){
    var newImage = context.createImageData(canvas.width, canvas.height);
    var arr = context.getImageData(0, 0, canvas.width, canvas.height);
    var pixels = arr.data;

    for(var i = 0; i < pixels.length; i+=4){
        var r = 255 - pixels[i];
        var g = 255 - pixels[i + 1];
        var b = 255 - pixels[i + 2];
        var a = pixels[i + 3];
        newImage.data[i] = r;
        newImage.data[i + 1] = g;
        newImage.data[i + 2] = b;
        newImage.data[i + 3] = a;
    }

    context.clearRect(0, 0, canvas.width, canvas.height);
    context.putImageData(newImage, 0, 0);
}

image_obj.src = 'http://www.johnchapple.com/jcwp/wp-content/uploads/2012/09/photography_quotes.jpg';
于 2013-09-29T16:53:21.597 回答