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我的问题是我需要在 div 类中的 div 类中获取 div 类，并且有 4 个具有相同名称但数据不同的类实例......我目前可以在 div 类中获取第一个 div 类但是我还需要能够访问其中的其他元素......例如：

docTide = Jsoup.connect("http://www.mhpa.co.uk/search-tide-times/").timeout(600000).get();
Elements tideTableRows = docTide.select("div.tide_row.odd");
Element firstDiv = tideTableRows.first();
Element secondDiv = tideTableRows.get(1);
System.out.println("This is the first div: " + firstDiv.text());
System.out.println("This is the second div: " + secondDiv.text());

但这是网页的结构，其中有 2 个重复，我需要访问它们中的每一个，例如：

 <div class="tide_row odd"> 
  <div class="time">00:57</div>
  <div class="height_m">4.9</div>
  <div class="height_f">16,1</div>
  <div class="range_m">1.9</div>
  <div class="range_f">6,3</div>
  </div>
 <div class="tide_row even">
  <div class="time">07:23</div>
  <div class="height_m">2.9</div>
  <div class="height_f">9,6</div>
  <div class="range_m">2</div>
  <div class="range_f">6,7</div>
  </div>
  <div class="tide_row odd">
  <div class="time">13:46</div>
  <div class="height_m">5.1</div>
  <div class="height_f">16,9</div>
  <div class="range_m">2.2</div>
  <div class="range_f">7,3</div>
  </div>
  <div class="tide_row even">
  <div class="time">20:23</div>
  <div class="height_m">2.8</div>
  <div class="height_f">9,2</div>
  <div class="range_m">2.3</div>
  <div class="range_f">7,7</div>
  </div>

所以基本上它在具有相同名称的单独类中嵌套了类，我怎样才能构造正确的语法来分别从类中返回数据？这很难解释！

编辑：这就是我设法从嵌套类中提取信息的方式：

 docTide = Jsoup.connect("http://www.mhpa.co.uk/search-tide-times/").timeout(600000).get();
                         Elements tideTimeOdd = docTide.select("div.tide_row.odd div:eq(0)");
                         Elements tideTimeEven = docTide.select("div.tide_row.even div:eq(0)");
                         Elements tideHightOdd = docTide.select("div.tide_row.odd div:eq(2)");
                         Elements tideHightEven = docTide.select("div.tide_row.even div:eq(2)");
                            Element firstTideTime = tideTimeOdd.first();
                            Element secondTideTime = tideTimeEven.first();
                            Element thirdTideTime = tideTimeOdd.get(1);
                            Element fourthTideTime = tideTimeEven.get(1);

                            Element firstTideHight = tideHightOdd.first();
                            Element secondTideHight = tideHightEven.first();
                            Element thirdTideHight = tideHightOdd.get(1);
                            Element fourthTideHight = tideHightEven.get(1);
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2 回答 2

1

你可以试试这个：

docTide = Jsoup.connect("http://www.mhpa.co.uk/search-tide-times/").timeout(600000).get();
Elements tideTableRows = docTide.select("div.tide_row");
for (Element tideTableRow : tideTableRows){
  if (tideTableRow.hasClass("odd")){
     //do the odd stuff...
  }
  Elements innerDivs = tideTableRows.select("div");

  for (Element innerDiv : innerDivs){
    //do whatever you need
  }
}

注意：代码未经测试。

更新：我向您展示了如何仅访问奇数行...我希望从那里您应该能够自己获得其余部分。

于 2013-09-29T14:13:26.090 回答
1

只需执行以下操作就可以正常工作：

 docTide = Jsoup.connect("http://www.mhpa.co.uk/search-tide-times/").timeout(600000).get();
                            Elements tideTableRows = docTide.select("div[class=tide_row odd]");
                            Element firstDiv += tideTableRows.select("div[class=time]");
                            Element secondDiv += tideTableRows.select("div[class=height]");

如果可以，您应该尝试通过 id 访问元素。它使您的代码更简单，例如，如果您在同一个容器中有 50 个标头，这样您就不必将它们全部计算在内。

分离元素：

 docTide = Jsoup.connect("http://www.mhpa.co.uk/search-tide-times/").timeout(600000).get();
                            Element tideTableRows = docTide.select("div[class=tide_row odd]").first();
                            Element firstDiv1 = tideTableRows.select("div[class=time]");
                            Element secondDiv1 = tideTableRows.select("div[class=height]");
                            tideTableRows2 = docTide.select("div[class=tide_row odd]").second();
                            Element firstDiv2 = tideTableRows.select("div[class=time]");
                            Element secondDiv2 = tideTableRows.select("div[class=height]");
于 2013-09-29T14:13:52.167 回答