我一直在谷歌搜索并在整个堆栈交换中搜索正确的答案,但我似乎找不到它。我所拥有的是通过弹出框 segue 呈现的弹出框视图,当在弹出框视图中单击按钮时,我希望将其关闭并显示 UIAlert。这是我到目前为止的代码,以及我从其他答案中收集到的但不起作用的代码:
- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender
{
if ([segue.identifier isEqualToString:@"popOverSegue"]) {
if ([segue isKindOfClass:[UIStoryboardPopoverSegue class]]) {
UIStoryboardPopoverSegue *popoverSegue = (UIStoryboardPopoverSegue *)segue;
self.myPopoverController = popoverSegue.popoverController;
}
}
}
- (void)methodThatShouldCauseMyPopoverToCloseAnimated:(BOOL)animated
{
[self.myPopoverController dismissPopoverAnimated:animated];
NSLog(@"Dismissed");
}
-(IBAction)presentPopoverView:(id)sender {
if (!popOverViewIsShown){
[self performSegueWithIdentifier:@"popOverSegue" sender:self];
popOverViewIsShown = YES;
}else {
[self methodThatShouldCauseMyPopoverToCloseAnimated:YES];
popOverViewIsShown = NO;
}
}
- (IBAction)logoutMethod:(id)sender {
[self methodThatShouldCauseMyPopoverToCloseAnimated:YES];
UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Logout"
message:@"Are you sure?"
delegate:self
cancelButtonTitle:@"Cancel"
otherButtonTitles:@"OK", nil];
alert.tag = 0;
[alert show];
}
我怀疑当我打电话时methodThatShouldCauseMyPopoverToClose
等于零myPopoverController
。有什么建议么?太感谢了!:)