php - 在同一个查询 where 和 like zend framework 2

Question

在哪里进行这样的查询，我该怎么办？

SELECT * FROM hotels WHERE name LIKE '%mykey%' AND country_id = '12'

我已经这样做了，但我们不能：

$select = $this->sql->select();
$select->from(self::TABLE);  

if ($params['key'])
{
   $where['where'] = new \Zend\Db\Sql\Predicate\Like('name', '%'.$params['key'].'%');
}

if($params['country_id'])
{
  $where['where'] = array(
      'country_id' => $params['country_id']
  );
}

$select->where($where['where']);
$select->order('id DESC');
$statement = $this->sql->prepareStatementForSqlObject($select);
return $statement->execute();

有义务使 if 语句改变查询的行为。我能怎么做？

Answer 1

$select = $this->sql->select();
$select->from(self::TABLE);  

if ($params['key'])
{
    $select->where->like('name', '%'.$params['key'].'%');
}

if($params['country_id'])
{
    $select->where(array('country_id' => $params['country_id']));
}

$select->order('id DESC');
$statement = $this->sql->prepareStatementForSqlObject($select);
return $statement->execute();