0

我有这个 XML:

<Envelope>
  <Body>
    <Response>
      <return>
        <contact_main>
          <firstname>John</firstname>
          <lastname>Doe</lastname>
          <error>false</error>
          <errors/>
        </contact_main>
        <contact_info1>
          <address1>High Road 748</address1>
          <zip>N17 0AP</zip>
          <city>London</city>
          <country_name>England</country_name>
          <error>true</error>
          <errors>
            <item>
              <text>Some error text here</text>
            </item>
          </errors>
        </contact_info1>
        <contact_card>
          <number>12345678</number>
          <status>Expired</status>
          <valid_to>2010-01-02Z</valid_to>
          <valid>false</valid>
          <error>true</error>
          <errors>
            <item>
              <text>Card is not valid.</text>
            </item>
          </errors>
        </contact_card>
      </return>
    </Response>
    <account_name>No name</account_name>
    <number>12345678</number>
  </Body>
</Envelope>

使用此 XSL:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl">
  <xsl:output method="xml" encoding="utf-8" indent="yes"/>

  <xsl:template match="Response">
    <response>
      <contact>
        <xsl:copy-of select="return/contact_main/node()"/>
        <xsl:copy-of select="return/contact_info1/node()"/>
      </contact>
      <card>
        <xsl:copy-of select="return/contact_card/node()"/>
      </card>
    </response>
  </xsl:template>

  <xsl:template match="account_name"/>
  <xsl:template match="number"/>

</xsl:stylesheet>

我得到以下结果:

<response>
  <contact>
    <firstname>John</firstname>
    <lastname>Doe</lastname>
    <error>false</error>
    <errors />

    <address1>High Road 748</address1>
    <zip>N17 0AP</zip>
    <city>London</city>
    <country_name>England</country_name>
    <error>true</error>
    <errors>
      <item>
        <text>Some error text here</text>
      </item>
    </errors>
  </contact>
  <card>
    <number>12345678</number>
    <status>Expired</status>
    <valid_to>2010-01-02Z</valid_to>
    <valid>false</valid>
    <error>true</error>
    <errors>
      <item>
        <text>Card is not valid.</text>
      </item>
    </errors>
  </card>
</response>

结果,有多个具有相同名称“error”和“errors”的节点。我想把它们从他们当前的父母那里拿出来,并将它们全部添加到 xml 的底部,所以我将有 1 个“错误”节点和 1 个“错误”数组,其中包含整个 xml 中的所有错误文本。

所以最终的 xml 将如下所示:

<response>
  <contact>
    <firstname>John</firstname>
    <lastname>Doe</lastname>
    <address1>High Road 748</address1>
    <zip>N17 0AP</zip>
    <city>London</city>
    <country_name>England</country_name>
  </contact>
  <card>
    <number>12345678</number>
    <status>Expired</status>
    <valid_to>2010-01-02Z</valid_to>
    <valid>false</valid>
  </card>
  <error>true</error>
  <errors>
    <text>Some error text here</text>
    <text>Card is not valid.</text>
  </errors>
</response>

这可能吗?

4

1 回答 1

0

您可以在复制时显式排除错误节点xsl:copy-of,然后计算error整个文档中的节点,如果计数大于零,则呈现“真”。

XLST 的简短示例:

    <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl">
      <xsl:output method="xml" encoding="utf-8" indent="yes"/>

      <xsl:template match="Response">
        <response>
          <contact>
            <xsl:copy-of select="return/contact_main/node()[local-name() != 'error' and local-name() != 'errors']"/>
            <xsl:copy-of select="return/contact_info1/node()[local-name() != 'error' and local-name() != 'errors']"/>
          </contact>
          <card>
            <xsl:copy-of select="return/contact_card/node()[local-name() != 'error' and local-name() != 'errors']"/>
          </card>

          <error><xsl:value-of select="count(return/*/error[text() = 'true']) &gt; 0"/></error>

          <errors>
             <xsl:for-each select="return/*/errors/item">
                 <xsl:copy-of select="text"/>
             </xsl:for-each>
          </errors>
        </response>
      </xsl:template>

      <xsl:template match="account_name"/>
      <xsl:template match="number"/>

    </xsl:stylesheet>

输出:

    <?xml version="1.0" encoding="utf-8"?>


        <response>
    <contact>
              <firstname>John</firstname>
              <lastname>Doe</lastname>



              <address1>High Road 748</address1>
              <zip>N17 0AP</zip>
              <city>London</city>
              <country_name>England</country_name>


            </contact>
    <card>
              <number>12345678</number>
              <status>Expired</status>
              <valid_to>2010-01-02Z</valid_to>
              <valid>false</valid>


            </card>
    <error>true</error>
    <errors>
    <text>Some error text here</text>
    <text>Card is not valid.</text>
    </errors>
    </response>
于 2013-09-27T08:43:04.880 回答