我需要从UISegmentedControl的选定部分显示弹出框,它是UIToolBar的子视图。这是我的代码:
// UISegemntedControl
NSArray *segments = [NSArray arrayWithObjects:@"one", @"two", @"three", nil];
_segmentedControl = [[UISegmentedControl alloc] initWithItems:segments];
_segmentedControl.frame = CGRectMake(self.frame.size.width/2-128, self.frame.size.height/2-12, 256, 24);
_segmentedControl.selectedSegmentIndex = 0;
[self addSubview:_segmentedControl];
显示弹出框:
- (void)show
{
UIView *view = [toolBar.segmentedControl.subviews objectAtIndex:toolBar.segmentedControl.selectedSegmentIndex];
// UIPopoverController
[popover presentPopoverFromRect:view.bounds inView:view permittedArrowDirections:UIPopoverArrowDirectionAny animated:YES];
}
它有效,但每次弹出窗口都来自错误的段。我不知道为什么...
更新: 解决方案:
float width = toolBar.segmentedControl.frame.size.width/toolBar.segmentedControl.subviews.count;
CGRect bounds = CGRectMake(toolBar.segmentedControl.frame.origin.x+width*toolBar.segmentedControl.selectedSegmentIndex, toolBar.segmentedControl.frame.origin.y, width, toolBat.segmentedControl.frame.size.height);
...
[popover presentPopoverFromRect:bounds inView:toolBar permittedArrowDirections:UIPopoverArrowDirectionAny animated:YES];