4 
var myArray = [
    '_aaaa_2013-09-25_ssss9.txt',
    '_aaaa_2013-09-25_ssss8.txt',
    '_aaaa_2013-09-26_ssss1.txt',
    '_aaaa_2013-09-25_ssss10.txt',
    '_aaaa_2013-09-26_ssss2.txt',
    '_aaaa_2013-09-25_ssss13.txt',
    '_aaaa_2013-09-25_ssss5.txt',
    '_aaaa_2013-09-25_ssss6.txt',
    '_aaaa_2013-09-25_ssss7.txt'
];

我需要按日期和数字对数组进行排序。

结果应该是 

var result = [
    '_aaaa_2013-09-25_ssss5.txt',
    '_aaaa_2013-09-25_ssss6.txt',
    '_aaaa_2013-09-25_ssss7.txt',
    '_aaaa_2013-09-25_ssss8.txt',
    '_aaaa_2013-09-25_ssss9.txt',
    '_aaaa_2013-09-25_ssss13.txt',
    '_aaaa_2013-09-26_ssss1.txt',
    '_aaaa_2013-09-26_ssss2.txt'
];

我试过下面的代码。这只会按日期排序，但我需要按“.txt”之前的数字排序。我该怎么做。

myArray.sort(function (a, b) {

    var timeStamp1 = a.substring(a.indexOf('_aaaa') + 6, a.indexOf('_ssss'));
    var timeStamp2 = b.substring(b.indexOf('_aaaa') + 6, b.indexOf('_ssss'));
    timeStamp1 = new Date(Date.UTC(timeStamp1[0], timeStamp1[1], timeStamp1[2]));
    timeStamp2 = new Date(Date.UTC(timeStamp2[0], timeStamp2[1], timeStamp2[2]));

    return (timeStamp1 > timeStamp2) ? 1 : (timeStamp2 > timeStamp1 ? -1 : 0);

});
4

4 回答 4

1

这对我有用。

myArray.sort(function (a, b) {
    var a_s = a.substring(0, a.indexOf('ssss') + 4);
    var a_n = a.substring(a.indexOf('ssss') + 4, a.indexOf('.txt'));
    var b_s = b.substring(0, b.indexOf('ssss') + 4);
    var b_n = b.substring(b.indexOf('ssss') + 4, b.indexOf('.txt'));
    if (a_s < b_s)
        return -1;
    if (a_s > b_s)
        return 1;
    return parseInt(a_n) - parseInt(b_n);
});

jsFiddle

于 2013-09-26T07:40:04.540 回答
1

你可以这样做：

var re = /^_aaaa_(\d\d\d\d-\d\d-\d\d)_ssss(\d+)\.txt$/;

var result = myArray.slice().sort( function( a, b ) {
    var aa = a.match(re), bb = b.match(re);
    return(
        aa[1] < bb[1] ? -1 :
        aa[1] > bb[1] ? 1 :
        aa[2] - bb[2]
    );
});

注意使用.slice()来创建数组的副本。如果要对原始数组进行就地排序，可以省略此项。（感谢@DerFlatulator 的提醒！）

于 2013-09-26T07:41:06.140 回答
0

这会从给定的字符串中提取数字，并对每个数字部分赋予给定的权重。因此，您可以使用给定的计数、日、月、年优先级按任何顺序对其进行排序。

function weightedNumSort(myArray,weightNum,weightString) {    
    var WEIGHTS_NUM = weightNum || [1,2,4,3]; //[YEAR,MONTH,DAY,COUNT], You can pass an array with appropriate weights for the number at the given position in the text, e.g year is the first Number
    var WEIGHT_STRING = weightString || 1; //And a weight for the string value. If none get passed, default weights are used

        function weightedSum (a,b,i) {
            return ( a  +  b * ( WEIGHTS_NUM [i-1] || 1 ));
        }

    myArray = myArray.slice().sort(function (a, b) {
        var reg = /(\d+)/g //A regex to extract the numerical part

        var lNum = a.match(reg) //Extract the numerical parts we now have an array ["2013","09","26","2"]

        var rNum = b.match(reg)

        var delta = Array.apply(null,{length:lNum.length+1});
            delta [0] = 0; //add a 0 at the beginning, for convenience with the reduce function

        for (var i=0,j=lNum.length; i < j; i++) {
            var value = lNum[i] - rNum[i];
            value = ~~ (value / Math.abs (value)) // 1 for positive values, 0 for 0 , -1 for negative values, to make weighting easier
            delta[i+1] = value;
        }

        var weightedNumValue = delta.reduce (weightedSum) //Put a weight on the number parts.
        var weightedStrValue = WEIGHT_STRING * ( a > b ? 1 : a < b ? -1 : 0 )    
        return weightedNumValue + weightedStrValue //Add the weighted values and we have a positive or negative value with a correct weight on the numerical parts
    })
    return  myArray
}

输出

console.log (
   weightedNumSort (myArray)    
) /*
[
  "_aaaa_2013-09-25_ssss5.txt",
  "_aaaa_2013-09-25_ssss6.txt",
  "_aaaa_2013-09-25_ssss7.txt",
  "_aaaa_2013-09-25_ssss8.txt",
  "_aaaa_2013-09-25_ssss9.txt",
  "_aaaa_2013-09-25_ssss10.txt",
  "_aaaa_2013-09-25_ssss13.txt",
  "_aaaa_2013-09-26_ssss1.txt",
  "_aaaa_2013-09-26_ssss2.txt"
]*/

和一个小提琴

于 2013-09-26T08:59:59.673 回答
0

按字符串中的数值排序。

这假设：

  • 数字是整数
  • 每个字符串都不一样
  • 日期可以按数字排序（年、月、日）

["aa_123","aa_13","aa_2","aa_22_bb_23","aa_22_bb_3"].sort( function ( a , b ) {

    var as = a.split(/([0-9]+)/); // splits string retaining separators
    var bs = b.split(/([0-9]+)/);
    var i,c = Math.min(as.length,bs.length);
    for ( i=0;i<c && as[i]===bs[i];++i ) ;
    var an = (i&1)?+as[i]:as[i]; // separators (digits) always at odd index
    var bn = (i&1)?+bs[i]:bs[i];
    return (an<bn)?-1:1; // assumes every string different

} );

结果：

[
  "aa_2",
  "aa_13",
  "aa_22_bb_3",
  "aa_22_bb_23",
  "aa_123"
]
于 2013-09-26T08:00:05.723 回答