0 
   /**
    * Fills the mutations array and sends to printMutations
    * @param firstString original DNA generation.
    */

   public static void mutation(String firstString)
   {
      final int ROWSINDEX = 26;
      final int SPACEUSED = firstString.length();


      char[][] mutations = new char[ROWSINDEX][SPACEUSED];
      String dnaChars = "AGTC";

      for (int i = 0; i < SPACEUSED; i++)
      {
         mutations[0][i] = firstString.charAt(i);
      }

      for (int i = 1; i < ROWSINDEX - 1; i++)
      {
         for (int j = 0; j < SPACEUSED; j++)
         {
            mutations[i][j] = mutations[i - 1][j];

          }
          int randomIndex = (int) (Math.random() * (SPACEUSED));
          int randomChar = (int) (Math.random() * (dnaChars.length()));
          mutations[i][randomIndex] = dnaChars.charAt(randomChar);  
         }
            printMutations(mutations, ROWSINDEX, SPACEUSED);
         }


   /**
    * Prints the 25 generations of mutations and the astrixes.
    * @param mutations array that holds the mutated generations
    * @param ROWSINDEX integer holding the max amount of rows possible
    * @param SPACEUSED integer that holds the number of columns
    */

   public static void printMutations(char[][] mutations, int ROWSINDEX, int SPACEUSED)
   {
      for (int i = 0; i < ROWSINDEX; i++)
      {
         for (int j = 0; j < SPACEUSED; j++)
         {
            System.out.print(" " +  mutations[i][j]); 
         }

         if (i > 0)
         {
            char[] a = mutations[i];
            char[] a2 = mutations[i - 1];
            if (Arrays.equals( a, a2 ) == true)
            {
               System.out.print("*");
            }
         }
         System.out.println("");
      }
   }
}

在输出结束时，您应该在模拟过程中未更改的任何字母的列下方打印一个星号。

该程序的示例运行应如下所示：

$ java BeckJ0926
Enter a DNA sequence up to 80 bp: ATTCGGCTA
ATTCGGCTA
ATCCGGCTA
ATCCGTCTA
ATCCGTCTA *
...
ATCCGTCTT
AACCGTCTT
AATCGTCTT
*  ** **

我不知道是否最好设置一个布尔数组来确定每一列是否发生了变化，这是我最初试图做的。我不能使用数组列表。

4

1 回答 1

0

你可以换行

mutations[i][randomIndex] = dnaChars.charAt(randomChar);

至

char currentChar = mutations[i][randomIndex];
if (currentChar == randomChar) {
    System.out.print("*");
} else {
    mutations[i][randomIndex] = dnaChars.charAt(randomChar);
    printMutation(mutations[i]);
}

并将打印功能更改为采用一种突变并打印它。

private void printMutation(char[] mutation) {
    for (char a : mutation) {
        System.out.print(a + " ");
    }
}

这有帮助吗？

于 2013-09-26T05:51:50.553 回答