我的问题是,如果 table 的值来自数据库,则 table 没有排序。
$sql=("SELECT *,SUM(unit_cost*quantity) AS total_amount FROM procurement WHERE rfq LIKE '13-___' GROUP BY counter ORDER BY rfq");
$result=mysql_query($sql);
echo'<table id="tfhover" cellspacing="0" class="tablesorter">
<thead>
<tr>
<th title="RFQ"></th>
<th title="RFQ">RFQ #</th>
<th title="Item Name">Item Name</th>
<th title="Item Description">Description</th>
<th title="Example : Pc, Pcs, Box and Etc.">Unit</th>
<th title="Item Price">Unit Cost</th>
<th title="Total Item Quantity">QTY</th>
<th title="Total Price">Total Amount</th>
</tr>
</thead>';
while($row = mysql_fetch_array($result)){
echo' <tbody>
<tr>
<td align="center"><a href="comments.php?pn='.$row["rfq"].'"><img src="images/remarks.png" border="0" width="10" height="10" title="Remarks and Notes"></a></td>
<td>'.$row['rfq'].'</td>
<td>'.$row['item_name'].'</td>
<td>'.$row['item_description'].'</td>
<td>'.$row['unit'].'</td>
<td>'.number_format($row['unit_cost'], 2, '.', ',').'</td>
<td>'.$row['quantity'].'</td>
<td>'.number_format($row['total_amount'], 2, '.', ',').'</td></tr></tbody>';
}
echo "</table>";
?>
但是当 table 的值不是来自数据库时,它可以完美地工作。我应该怎么办?
<tr>
<th>Major</th>
<th>Gender</th>
<th>English</th>
<th>Japanese</th>
<th>Calculus</th>
<th>Geometry</th>
</tr>
</thead>
<tbody>
<tr>
<td>Student01</td>
<td>Languages</td>
<td>male</td>
<td></td>
<td>70</td>
<td></td>
</tr>
<tr>
<td>Student02</td>
<td>Mathematics</td>
<td>male</td>
<td>90</td>
<td>88</td>
<td></td>
</tr>
<tr>
<td>Student03</td>
<td>Languages</td>
<td>female</td>
<td>85</td>
<td>95</td>
<td>80</td>
</tr>
</tbody>
</table>