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我试图在 MVC4 RAZOR 应用程序中单击按钮后将所选单选按钮的值发回控制器。然而,我没有在控制器中取回真正的期望值,只有 0。

部分查看代码:

@model Blah.FeatureViewModel
<script type="text/javascript">
    function OnContinueClick() {
        $('#tabs').load('@Url.Action("Continue", "Home")', { SelectedFeature : Model.SelectedFeature });
    }
</script> 

@using (Html.BeginForm())
{
    <div>
        @foreach (var feature in Model.FeatureDictionary)
        {
            <p>
                @Html.RadioButtonFor(x => x.SelectedFeature, feature) @feature.Value
            </p>       
        }

        <input type="button" name="continueButton" id="continueButton" value="Continue" onclick="OnContinueClick()" />
    </div>
}

查看型号代码:

using System.Collections.Generic;

namespace Blah.Models
{
    public class FeatureViewModel
    {
        public Dictionary<int, string> FeatureDictionary { get; set; }
        public KeyValuePair<int, string> SelectedFeature { get; set; }
    }
}

控制器代码:

[HttpPost]
public ActionResult Continue(FeatureViewModel featureViewModel)
{
    //pass data to another controller
}

我想我可能需要 Jquery 来回发值?

4

1 回答 1

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您传递给 jQueryload函数的值是视图呈现时模型的值。要传递当前选择的值,您需要这样:

$('#tabs').load('@Url.Action("Continue", "Home")',
                { SelectedFeature : $('[name="SelectedFeature"]').val() });

同样正如Joel Etherton所说,您需要将操作的类型从 更改FeatureViewModelKeyValuePair<int, string>

我不确定

@Html.RadioButtonFor(x => x.SelectedFeature, feature)

是给你想要的,因为特性是KeyValuePair<int, string>. 你试图创建一个单选按钮是什么?

于 2013-09-25T20:35:14.937 回答