4

我试着玩一下表达式树。我有一个带有 a 的对象,List<string>我想构建一个表达式树,为该属性添加一个值,但我想通过 a 指定要添加的值Func。目前我尝试这个...

public static Action<T> CreateMethodAddObjectToList<T, C>(this Type type, string property, Func<C> ctorFunction)
        {
            PropertyInfo fieldInfo = type.GetProperty(property);

            if (fieldInfo == null)
            {
                return null;
            }

            ParameterExpression targetExp = Expression.Parameter(type, "target");
            MemberExpression fieldExp = Expression.Property(targetExp, property);
            var method = fieldExp.Type.GetMethod("Add", BindingFlags.Public | BindingFlags.Instance);

            Expression<Func<C>> ctorExpression = () => ctorFunction();

// but this doesnt work because I can't use the ctorExpression in this way
            var callExp = Expression.Call(fieldExp, method, ctorExpression);

            var function = Expression.Lambda<Action<T>>(callExp, targetExp).Compile();

            return function;
        }

电话看起来像

var dummyObject = new DummyObject { IntProperty = 5 };

            Action<DummyObject> setter = typeof (DummyObject).CreateMethodAddObjectToList<DummyObject, string>("StringList", () => "Test" );
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1 回答 1

1

您可以将 ctorFunction 更改为 an Expression<Func<C>>,然后在生成的操作中调用它:

public static Action<T> CreateMethodAddObjectToList<T, C>(this Type type, string property, Expression<Func<C>> createExpr)
{
    PropertyInfo fieldInfo = type.GetProperty(property);

    if (fieldInfo == null)
    {
        return null;
    }

    ParameterExpression targetExp = Expression.Parameter(type, "target");
    MemberExpression fieldExp = Expression.Property(targetExp, property);
    var method = fieldExp.Type.GetMethod("Add", BindingFlags.Public | BindingFlags.Instance);

    var valueExpr = Expression.Invoke(createExpr);
    var callExpr = Expression.Call(fieldExp, method, valueExpr);

    var function = Expression.Lambda<Action<T>>(callExpr, targetExp).Compile();

    return function;
}
于 2013-09-26T10:32:33.867 回答