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我正在尝试使用 EclipseLink MOXy（JSON 绑定）将 JSON 字符串转换为 Java 对象。当 JSON 字符串包含“\”字符时，我收到以下异常。下面是我正在尝试做的示例程序。我应该怎么做才能转义反斜杠，以便将 TestBean 中的 name 属性填充为“A\B”？

import java.io.StringReader;
import javax.xml.bind.JAXBContext;
import javax.xml.bind.JAXBException;
import javax.xml.bind.Unmarshaller;
import javax.xml.transform.stream.StreamSource;
import org.eclipse.persistence.jaxb.UnmarshallerProperties;

public class JSONMoxyTest {

    public static void main(String[] args) throws JAXBException {
        Unmarshaller unmarshaller = JAXBContext.newInstance(TestBean.class).createUnmarshaller();
        unmarshaller.setProperty(UnmarshallerProperties.MEDIA_TYPE, "application/json");
        unmarshaller.setProperty(UnmarshallerProperties.JSON_INCLUDE_ROOT, false);
        String jsonStr = "{\"name\":\"A\\B\"}"; //{"name":"A\B"}
        TestBean bean = unmarshaller.unmarshal(new StreamSource(new StringReader(jsonStr )), TestBean.class).getValue();
        System.out.println(bean.getName());
    }
}

class TestBean {
  private String name;
  public String getName() {
    return name;
  }
  public void setName(String name) {
    this.name = name;
  }
}

Exception:
line 1:10 no viable alternative at character '\'
line 1:11 no viable alternative at character 'B'
line 1:14 mismatched character '<EOF>' expecting '"'
line 0:-1 no viable alternative at input '<EOF>'
Exception in thread "main" javax.xml.bind.UnmarshalException
 - with linked exception:
[Exception [EclipseLink-25004] (Eclipse Persistence Services - 2.5.0.v20130507-3faac2b): org.eclipse.persistence.exceptions.XMLMarshalException
Exception Description: An error occurred unmarshalling the document
Internal Exception: NoViableAltException(-1@[])]
    at org.eclipse.persistence.jaxb.JAXBUnmarshaller.handleXMLMarshalException(JAXBUnmarshaller.java:980)
    at org.eclipse.persistence.jaxb.JAXBUnmarshaller.unmarshal(JAXBUnmarshaller.java:303)
    at org.gs1us.glnreg.util.usps.JSONMoxyTest.main(JSONMoxyTest.java:17)
Caused by: Exception [EclipseLink-25004] (Eclipse Persistence Services - 2.5.0.v20130507-3faac2b): org.eclipse.persistence.exceptions.XMLMarshalException
Exception Description: An error occurred unmarshalling the document
Internal Exception: NoViableAltException(-1@[])
    at org.eclipse.persistence.exceptions.XMLMarshalException.unmarshalException(XMLMarshalException.java:113)
    at org.eclipse.persistence.internal.oxm.record.SAXUnmarshaller.convertSAXException(SAXUnmarshaller.java:996)
    at org.eclipse.persistence.internal.oxm.record.SAXUnmarshaller.unmarshal(SAXUnmarshaller.java:984)
    at org.eclipse.persistence.internal.oxm.record.SAXUnmarshaller.unmarshal(SAXUnmarshaller.java:425)
    at org.eclipse.persistence.internal.oxm.record.SAXUnmarshaller.unmarshal(SAXUnmarshaller.java:635)
    at org.eclipse.persistence.internal.oxm.record.SAXUnmarshaller.unmarshal(SAXUnmarshaller.java:703)
    at org.eclipse.persistence.oxm.XMLUnmarshaller.unmarshal(XMLUnmarshaller.java:655)
    at org.eclipse.persistence.jaxb.JAXBUnmarshaller.unmarshal(JAXBUnmarshaller.java:301)
    ... 1 more
Caused by: NoViableAltException(-1@[])
    at org.eclipse.persistence.internal.oxm.record.json.JSONParser.value(JSONParser.java:673)
    at org.eclipse.persistence.internal.oxm.record.json.JSONParser.pair(JSONParser.java:372)
    at org.eclipse.persistence.internal.oxm.record.json.JSONParser.object(JSONParser.java:224)
    at org.eclipse.persistence.internal.oxm.record.json.JSONParser.message(JSONParser.java:127)
    at org.eclipse.persistence.internal.oxm.record.json.JSONReader.parse(JSONReader.java:124)
    at org.eclipse.persistence.internal.oxm.record.SAXUnmarshaller.unmarshal(SAXUnmarshaller.java:972)
    ... 6 more

我正在使用这些罐子：org.eclipse.persistence.antlr-2.5.0.jar、org.eclipse.persistence.asm-2.5.0.jar、org.eclipse.persistence.core-2.5.0.jar、org. eclipse.persistence.moxy-2.5.0.jar

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1 回答 1

1

在 JSON 中，\字符必须转义为\\.

已更正JSONMoxyTest

import java.io.StringReader;
import javax.xml.bind.*;
import javax.xml.transform.stream.StreamSource;
import org.eclipse.persistence.jaxb.UnmarshallerProperties;

public class JSONMoxyTest {

    public static void main(String[] args) throws JAXBException {
        Unmarshaller unmarshaller = JAXBContext.newInstance(TestBean.class).createUnmarshaller();
        unmarshaller.setProperty(UnmarshallerProperties.MEDIA_TYPE, "application/json");
        unmarshaller.setProperty(UnmarshallerProperties.JSON_INCLUDE_ROOT, false);
        String jsonStr = "{\"name\":\"A\\\\B\"}"; //{"name":"A\\B"}
        TestBean bean = unmarshaller.unmarshal(new StreamSource(new StringReader(jsonStr )), TestBean.class).getValue();
        System.out.println(bean.getName());
    }

}

输出

A\B
于 2013-09-25T13:17:51.463 回答