我实际上有这个 PHP 代码,我用它来获取我的数据库信息..
function searchUserEmail($username, $raw_email){
//Prepare Statements
$query = "SELECT * FROM users WHERE username = ?";
$query2 = "SELECT * FROM users WHERE email = ?";
//Sanitize Input
$user = $this->conn->real_escape_string($username);
$email = $this->conn->real_escape_string($raw_email);
if($stmt = $this->conn->prepare($query)){
$stmt->bind_param('s', $user);
$stmt->execute();
if($stmt->num_rows > 0){
$stmt->close();
return true;
}
}
if($stmt = $this->conn->prepare($query2)){
$stmt->bind_param('s', $email);
$stmt->execute();
if($stmt->num_rows > 0){
$stmt->close();
return true;
}
}
return false;
}
我已经尝试了很多次,通过语句检查器运行它,仍然无法正常工作。有什么我想念的吗???
不知何故,它总是返回一个假(即使它假设返回真)