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我在 Android 中开发了一个基于测验的应用程序。现在，当我尝试按递减顺序排列高分时，问题就出现了。我收到错误invalid LIMIT clauses:score DESC。我在这里发布了我的数据库类和我试图以递减顺序从中获取高分的类。请帮我解决这个错误。

DBAdapter.java

public long addscore(String name, int score)
{

    ContentValues values = new ContentValues();
    values.put(KEY_name, name); 
    values.put(KEY_score, score);

    return db.insert(DATABASE_TABLE1, null, values);
}
public Cursor getScore() throws SQLException 
{

    String order = KEY_score + " DESC ";
    /*return db.query(DATABASE_TABLE1, new String[] {KEY_scoreid, KEY_name,
            KEY_score}, null, null, null, null, order);*/
    Cursor mCursor = db.query(true, DATABASE_TABLE1, new String[] {
            KEY_scoreid, KEY_name,KEY_score },null, null,null,null, null,order);
    if (mCursor != null) 
    {
        mCursor.moveToFirst();
    }
    return mCursor;
}

高分.java

    try
    {
        db1=new DBAdapter(this);
        db1.open();
        c=db1.getScore();

        n1=c.getString(1);
        s1=c.getInt(2);
        n2=c.getString(1);
        s2=c.getInt(2);
        n3=c.getString(1);
        s3=c.getInt(2);
        n4=c.getString(1);
        s4=c.getInt(2);
        n5=c.getString(1);
        s5=c.getInt(2);

        name1.setText(n1);
        score1.setText(Integer.toString(s1));
        name2.setText(n2);
        score2.setText(Integer.toString(s2));
        name3.setText(n3);
        score3.setText(Integer.toString(s3));
        name4.setText(n4);
        score4.setText(Integer.toString(s4));
        name5.setText(n5);
        score5.setText(Integer.toString(s5));

    }
    catch(Exception ex)
    {
        Toast.makeText(getBaseContext(), ex.getMessage(), Toast.LENGTH_SHORT).show();
    }

我需要你们的帮助，请帮助！

提前致谢。

4

2 回答 2

0

查询应该是这样的

Cursor mCursor = db.query(true, DATABASE_TABLE1, new String[] {
            KEY_scoreid, KEY_name,KEY_score },null, null,null,null,KEY_score + " DESC",null);
于 2013-09-24T10:13:04.740 回答
0

尝试如下：

Cursor mCursor =db.query(DATABASE_TABLE1, new String[] {KEY_scoreid,KEY_name,KEY_score}, null, null, null, null, KEY_score + " DESC");

编辑：

if (cur.getCount() > 0)
            {
                if (cur.moveToFirst())
                {
                    do
                    {
                        id1 = cur.getInt(0);
                        name = cur.getString(1);
                       Contacts contact_list = new Contacts(id1, name);
                        contact.add(contact_list);
                    } 
                    while (cur.moveToNext());
                }
                cur.deactivate();
                cur.close();
                cdb.close();
            }

你Contact的位置如下：

public class Contacts
{
    private int Id;
    private String NAME;
    public int getId()
    {
        return Id;
    }
    public void setId(int id)
    {
        this.Id = id;
    }
    public String getNAME()
    {
        return NAME;
    }
    public void setNAME(String name)
    {
        NAME = name;
    }
     public Contacts(int id, String name)
    {
        super();
        this.Id = id;
        NAME = name;
    }
}
于 2013-09-24T10:33:28.550 回答