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我正在尝试设置一个推文按钮。我所有的代码似乎都在工作,除了它给了我错误“选择器'canSendTweet'没有已知的类方法”有什么建议吗?

- (IBAction)tweetTapped:(id)sender
{
//Check if the device can send tweets
if ([SLComposeViewController canSendTweet])
{
    //Create tweet sheet and set initial text
   SLComposeViewController *tweetSheet =
    [[SLComposeViewController alloc] init];
    [tweetSheet setInitialText:@"this is a tweet from my app"];
    [tweetSheet addURL:[NSURL URLWithString:@"http://www.iosdeveloperguide.com"]];

    //show tweet sheet
    [self presentViewController:tweetSheet animated:YES completion:nil];
}
else
{
    //Device can not tweet. Show error Notification.
    UIAlertView *alertview = [[UIAlertView alloc]
                              initWithTitle:@"Unable to Tweet"
                              message:@"Please ensure that you have at least one Twitter account setup and have internet connectivity"
                              delegate:self
                              cancelButtonTitle:@"OK"
                              otherButtonTitles:nil];
    [alertview show];

}

}


 @end
4

2 回答 2

2

没有为该类命名canSendTweet的此类方法SLComposeViewController。快速查看参考文档(您应该这样做)表明您想要的是:

if ([SLComposeViewController isAvailableForServiceType:SLServiceTypeTwitter]) {
    // can send a tweet
}
于 2013-09-24T03:03:41.713 回答
0
canSendTweet 

这是来自 Twitter.framework 的方法(你必须导入这个框架)

您可以在 Social.framework 中使用此方法来检查“用户可以发推文吗?”

if ([SLComposeViewController isAvailableForServiceType:SLServiceTypeTwitter]) {
    // can send a tweet
}
于 2013-09-24T03:14:22.470 回答