scala - 播放异常：“{”预期但发现“导入”

Question

它向我抛出了第 3 行的异常。问题是我只有以下几行：

package controllers

import play.api._
import play.api.mvc._
import views._
import models._

object Application extends Controller {

  def index = Ok(views.html.index("grrr", "blabla"))

}

编辑：index.scala.html

@import helper._

@main("Todo") {

    <h1>Hello World</h1>

}

我在 windows xp 上使用 play 2.2.0 (with sbt)

Answer 1

I think that problem is with yours line separator in IDE. I once change LF(Linux) to CR(Mac)(by mistake, not knowing that this has an impact on compilation) and struggle with the same problem. After changing to default sperator everything back to normal.

Answer 2

Play 中的第一行！模板是为签名定义保留的。Welcome当您创建新的 Play 应用程序时，屏幕中也会提到这一点。

除了为什么要导入的问题之外helper._，我会执行以下操作：

1. 使第一行为空，或者至少没有导入语句。
2. 跑play clean
3. 在此之后它应该可以工作，我希望:-)

更多的信息：

• 播放框架模板自动导入模型。_除其他外
• https://github.com/playframework/playframework/blob/1acfd1dc4264e7589876fb1f4ebf37e584ab8bc6/framework/src/play/src/main/scala/views/play20/welcome.scala.html#L81
• If you know a bit scala (I don't yet): https://github.com/playframework/playframework/blob/9206bea8c9c88acdc6786ebb2554f081396e8f6a/framework/src/templates-compiler/src/main/scala/play/templates/ScalaTemplateCompiler.scala

EDIT: 2013.09.24 at 22:15

You are passing two arguments to your view template (views.html.index("grrr", "blabla")), (views are compiled to functions). So in your function (`index view') the first line SHOULD define the function signature (arguments). I think that you should write your template as:

@(firstString : String, secondString : String)

@import helper._

@main("Todo") {

    <h1>Hello World</h1>

}