是的，这是作业，不，我不是要你做我的作业。我需要关于这个二元炸弹第 3 阶段的帮助。第 1 阶段和第 2 阶段我没有遇到任何问题，但第 3 阶段对我来说太过分了。我知道应该有3个输入。我很确定其中一个是字符输入，其中两个是整数，但我不确定顺序是什么。首先，这是反汇编代码：
0x0000000000401163 <phase_3+0>: sub $0x18,%rsp
0x0000000000401167 <phase_3+4>: lea 0xf(%rsp),%rcx
0x000000000040116c <phase_3+9>: lea 0x14(%rsp),%rdx
0x0000000000401171 <phase_3+14>: lea 0x10(%rsp),%r8
0x0000000000401176 <phase_3+19>: mov $0x402650,%esi
0x000000000040117b <phase_3+24>: mov $0x0,%eax
0x0000000000401180 <phase_3+29>: callq 0x400b80 <sscanf@plt>
0x0000000000401185 <phase_3+34>: cmp $0x2,%eax
0x0000000000401188 <phase_3+37>: jg 0x40118f <phase_3+44>
0x000000000040118a <phase_3+39>: callq 0x4014b1 <explode_bomb>
0x000000000040118f <phase_3+44>: cmpl $0x7,0x14(%rsp)
0x0000000000401194 <phase_3+49>: ja 0x401294 <phase_3+305>
0x000000000040119a <phase_3+55>: mov 0x14(%rsp),%eax
0x000000000040119e <phase_3+59>: xchg %ax,%ax
0x00000000004011a0 <phase_3+61>: jmpq *0x402660(,%rax,8)
0x00000000004011a7 <phase_3+68>: cmpl $0x2c4,0x10(%rsp)
0x00000000004011af <phase_3+76>: nop
0x00000000004011b0 <phase_3+77>: je 0x4012a2 <phase_3+319>
0x00000000004011b6 <phase_3+83>: callq 0x4014b1 <explode_bomb>
0x00000000004011bb <phase_3+88>: mov $0x7a,%eax
0x00000000004011c0 <phase_3+93>: jmpq 0x4012a7 <phase_3+324>
0x00000000004011c5 <phase_3+98>: mov $0x6a,%eax
---Type <return> to continue, or q <return> to quit---
0x00000000004011ca <phase_3+103>: cmpl $0x327,0x10(%rsp)
0x00000000004011d2 <phase_3+111>: je 0x4012a7 <phase_3+324>
0x00000000004011d8 <phase_3+117>: callq 0x4014b1 <explode_bomb>
0x00000000004011dd <phase_3+122>: mov $0x6a,%eax
0x00000000004011e2 <phase_3+127>: jmpq 0x4012a7 <phase_3+324>
0x00000000004011e7 <phase_3+132>: mov $0x66,%eax
0x00000000004011ec <phase_3+137>: cmpl $0x136,0x10(%rsp)
0x00000000004011f4 <phase_3+145>: je 0x4012a7 <phase_3+324>
0x00000000004011fa <phase_3+151>: callq 0x4014b1 <explode_bomb>
0x00000000004011ff <phase_3+156>: mov $0x66,%eax
0x0000000000401204 <phase_3+161>: jmpq 0x4012a7 <phase_3+324>
0x0000000000401209 <phase_3+166>: mov $0x75,%eax
0x000000000040120e <phase_3+171>: cmpl $0x252,0x10(%rsp)
0x0000000000401216 <phase_3+179>: je 0x4012a7 <phase_3+324>
0x000000000040121c <phase_3+185>: callq 0x4014b1 <explode_bomb>
0x0000000000401221 <phase_3+190>: mov $0x75,%eax
0x0000000000401226 <phase_3+195>: jmpq 0x4012a7 <phase_3+324>
0x000000000040122b <phase_3+200>: mov $0x70,%eax
0x0000000000401230 <phase_3+205>: cmpl $0x240,0x10(%rsp)
0x0000000000401238 <phase_3+213>: je 0x4012a7 <phase_3+324>
0x000000000040123a <phase_3+215>: callq 0x4014b1 <explode_bomb>
0x000000000040123f <phase_3+220>: mov $0x70,%eax
0x0000000000401244 <phase_3+225>: jmp 0x4012a7 <phase_3+324>
---Type <return> to continue, or q <return> to quit---
0x0000000000401246 <phase_3+227>: cmpl $0x269,0x10(%rsp)
0x000000000040124e <phase_3+235>: xchg %ax,%ax
0x0000000000401250 <phase_3+237>: je 0x4012a2 <phase_3+319>
0x0000000000401252 <phase_3+239>: callq 0x4014b1 <explode_bomb>
0x0000000000401257 <phase_3+244>: mov $0x7a,%eax
0x000000000040125c <phase_3+249>: jmp 0x4012a7 <phase_3+324>
0x000000000040125e <phase_3+251>: mov $0x6b,%eax
0x0000000000401263 <phase_3+256>: cmpl $0x201,0x10(%rsp)
0x000000000040126b <phase_3+264>: je 0x4012a7 <phase_3+324>
0x000000000040126d <phase_3+266>: callq 0x4014b1 <explode_bomb>
0x0000000000401272 <phase_3+271>: mov $0x6b,%eax
0x0000000000401277 <phase_3+276>: jmp 0x4012a7 <phase_3+324>
0x0000000000401279 <phase_3+278>: mov $0x74,%eax
0x000000000040127e <phase_3+283>: cmpl $0x358,0x10(%rsp)
0x0000000000401286 <phase_3+291>: je 0x4012a7 <phase_3+324>
0x0000000000401288 <phase_3+293>: callq 0x4014b1 <explode_bomb>
0x000000000040128d <phase_3+298>: mov $0x74,%eax
0x0000000000401292 <phase_3+303>: jmp 0x4012a7 <phase_3+324>
0x0000000000401294 <phase_3+305>: callq 0x4014b1 <explode_bomb>
0x0000000000401299 <phase_3+310>: mov $0x75,%eax
0x000000000040129e <phase_3+315>: xchg %ax,%ax
0x00000000004012a0 <phase_3+317>: jmp 0x4012a7 <phase_3+324>
0x00000000004012a2 <phase_3+319>: mov $0x7a,%eax
---Type <return> to continue, or q <return> to quit---
0x00000000004012a7 <phase_3+324>: cmp 0xf(%rsp),%al
0x00000000004012ab <phase_3+328>: je 0x4012b2 <phase_3+335>
0x00000000004012ad <phase_3+330>: callq 0x4014b1 <explode_bomb>
0x00000000004012b2 <phase_3+335>: add $0x18,%rsp
0x00000000004012b6 <phase_3+339>: retq
我输入了 4 112 z 之类的东西，只是为了尝试一下并完成这些步骤。
代码运行到0x0000000000401230 <phase_3+205>: cmpl $0x240,0x10(%rsp)
我真正感到困惑的是 0x10(%rsp) 表示什么。我查看了存储在 rsp 中的十进制值，它是负数。似乎 4 的第一个输入运行良好，并且代码继续运行，但我想知道为什么它将 rsp 与 576 进行比较，以及它前面的 0x10 表示什么。任何形式的洞察力都会有所帮助。