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我有以下具有四个QGraphicView对象 的 GUI在此处输入图像描述

它有四个工具按钮,您可以在每个视图下看到。为了最大化视图,我连接了工具按钮的信号以隐藏其他三个视图的插槽,并将大小策略设置为扩展所有四个视图。但它仅适用于 View1 和 View 4 其他视图显示以下结果:

在此处输入图像描述

我正在使用网格布局。View2 在左侧留下空隙,View3 在右侧留下空隙。当我隐藏剩余时,我没有任何理由说明 View 2 和 View 3 会留下空隙。

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1 回答 1

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下面的代码在 Qt 4 和 Qt 5 下都适用于我。它利用状态机框架来简化状态转换的管理。一个视图可见的状态是不显示视图的状态的子状态。这消除了对显式信号槽连接以及保留视图和按钮列表的需要。

该类State仅用于调试目的,以可视化状态转换。

唉,至少在 Qt 4.8.5 中存在一个错误(种族?),这使得属性分配并不总是在嵌套状态下正常工作。当使用具有重叠属性的嵌套状态时,有时尽管机器已进入正确状态,但所有视图和按钮都会被隐藏。下面的代码中有一个解决方法。

请注意,网格小部件不得有任何其他小部件的行/列跨度!= 1。如果有,隐藏小部件周围的间距仍然可见。这就是我使用两个嵌套布局的原因。

#include <QApplication>
#include <QWidget>
#include <QGridLayout>
#include <QPushButton>
#include <QGraphicsView>
#include <QGraphicsScene>
#include <QStateMachine>
#include <QPlainTextEdit>
#include <QPointer>

static const int N = 4;
static QPointer<QPlainTextEdit> logView;

class State : public QState
{
public:
    explicit State(const QString& name, QState* parent = 0) : QState(parent) {
        setObjectName(name);
    }
protected:
    virtual void onEntry(QEvent*) {
        QString state = objectName();
        QState* parent = this;
        while ((parent = parent->parentState()) && !parent->objectName().isEmpty() )
        {
            state = parent->objectName() + "->" + state;
        }
        logView->appendHtml(QString("<font color=\"green\">Entering state: <b>%1</b></font>").arg(state));
    }
    virtual void onExit(QEvent*) {
        QString state = objectName();
        QState* parent = this;
        while ((parent = parent->parentState()) && !parent->objectName().isEmpty() )
        {
            state = parent->objectName() + "->" + state;
        }
        logView->appendHtml(QString("<font color=\"red\">Exiting state: <b>%1</b></font>").arg(state));
    }
};

class Widget : public QWidget {
public:
    explicit Widget(bool qt4) {
        QGridLayout *vert = new QGridLayout(this);
        QGridLayout *layout = new QGridLayout;
        layout->setContentsMargins(0, 0, 0, 0);
        logView = new QPlainTextEdit;
        logView->appendPlainText(QString("Qt %1").arg(QT_VERSION_STR));
        vert->addLayout(layout, 0, 0, 1, 1);
        vert->addWidget(logView, 1, 0, 1, 1);
        QStateMachine * const machine = new QStateMachine(this);
        machine->setObjectName("machine");
        State * const all = new State("all", machine);
        State * const none = new State("none", machine);
        QList<QState*> ones;
        for (int i = 0; i < N; ++ i) {
            const QString label = QString("View %1").arg(i+1);
            ones << new State(label, none);
        }
        for (int i = 0; i < N; ++ i) {
            QState *one = ones[i];
            QGraphicsView *view = new QGraphicsView;
            QGraphicsScene *scene = new QGraphicsScene(view);
            scene->addText(one->objectName());
            view->setScene(scene);
            layout->addWidget(view, 2*(i/2), i%2, 1, 1);
            QPushButton *button = new QPushButton(one->objectName());
            layout->addWidget(button, 2*(i/2)+1, i%2, 1, 1);
            button->setSizePolicy(QSizePolicy::Maximum, QSizePolicy::Fixed);
            all->assignProperty(view, "visible", true);
            all->assignProperty(button, "visible", true);
            if (qt4) {
                // Workaround for a bug: properties in nested states are
                // sometimes not set correctly, so we explicitly set all properties
                // in one state.
                foreach (QState* s, ones) {
                    s->assignProperty(view, "visible", s == one);
                    s->assignProperty(button, "visible", s == one);
                }
            } else {
                none->assignProperty(view, "visible", false);
                none->assignProperty(button, "visible", false);
                one->assignProperty(view, "visible", true);
                one->assignProperty(button, "visible", true);
            }
            all->addTransition(button, SIGNAL(clicked()), one);
            one->addTransition(button, SIGNAL(clicked()), all);
            if (!none->initialState()) none->setInitialState(one);
        }
        machine->setInitialState(all);
        machine->start();
    }
};

int main(int argc, char *argv[])
{
    QApplication a(argc, argv);
    Widget w(QT_VERSION < QT_VERSION_CHECK(5,0,0));
    w.show();
    return a.exec();
}
于 2013-09-23T14:30:29.240 回答