1

我对 Oracle 中的查询有疑问：

问题是，结果oci_num_rows始终为 0。

到目前为止，这是我的代码：

  $query = "SELECT IP_ADDRESS, STATUS FROM SEIAPPS_IP_ADDRESS WHERE IP_ADDRESS='$ip'";
  $result = oci_parse($c1, $query);
  oci_execute($result);
  echo $found = oci_num_rows($result);

为了确保这一点，我尝试清除条件"WHERE IP_ADDRESS='$ip'"。结果仍然是 0 而在我的表中有一些数据。

有什么建议吗？

4

3 回答 3

5

用这个：

$query = "SELECT IP_ADDRESS, STATUS FROM SEIAPPS_IP_ADDRESS WHERE IP_ADDRESS='$ip'";
$result = oci_parse($c1, $query);
oci_execute($result);
$numrows = oci_fetch_all($result, $res);
echo $numrows." Rows";
于 2013-09-23T10:51:05.737 回答
4

此函数不返回选择的行数！对于SELECT statements此函数，将返回使用oci_fetch*()函数提取到缓冲区的行数。

试试这个来检查你的连接凭据是否正确。

<?php
$conn = oci_connect("hr", "welcome", "localhost/XE");
if (!$conn) {
    $e = oci_error();   // For oci_connect errors do not pass a handle
    trigger_error(htmlentities($e['message']), E_USER_ERROR);
}
?>
于 2013-09-23T10:40:11.647 回答
2

对于掉入这个陷阱的其他人，这里是该oci_fetch_all方法将返回的内容的简单摘要。

$s = oci_parse($conn, "
          SELECT 1 AS A FROM DUAL 
    UNION SELECT 2 AS A FROM DUAL 
    UNION SELECT 3 AS A FROM DUAL 
    UNION SELECT 4 AS A FROM DUAL
");
oci_execute($s);
echo "records fetched: ". oci_num_rows($s)."\n";

oci_fetch($s);
echo "records fetched: ". oci_num_rows($s)."\n";

oci_fetch($s);
echo "records fetched: ". oci_num_rows($s)."\n";

oci_fetch_all($s, $out);
echo "records fetched: ". oci_num_rows($s)." out count: ". count($out['A']) . "\n";

将输出：

records fetched: 0
records fetched: 1
records fetched: 2
records fetched: 4 out count: 2

增量也是如此oci_num_rows，每次调用oci_fetch都会将计数器加一（假设至少还有一条记录要获取），oci_fetch_all并将获取所有剩余的行并将它们放入$out缓冲区。

于 2016-01-05T11:46:01.593 回答