1

我正在尝试从 sqlite db 对我的 listview 项目进行排序。

这是我迄今为止尝试过的：

 final String[] categories = {
        "Firstname", "Lastname", "Last check up"
};

 @Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.viewallpatients);

 ArrayAdapter<String> adapter = new ArrayAdapter<String> 
        (this,android.R.layout.simple_spinner_item, categories);
    spinner = (Spinner) findViewById (R.id.spCategory);
    adapter.setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item);
    spinner.setAdapter(adapter);
    spinner.setOnItemSelectedListener(this);

   }

 @Override
public void onItemSelected(AdapterView<?> parent, View v, int position,
        long id) {
    // TODO Auto-generated method stub
    final String f = parent.getItemAtPosition(position).toString();

    switch(position){
    case 0:
        ca.setFilterQueryProvider(new FilterQueryProvider() {
             public Cursor runQuery(CharSequence constraint) {
                 return dbHelper.sortByFirstname(f);
             }
        }); 

        break;
    case 1:
        ca.setFilterQueryProvider(new FilterQueryProvider() {
             public Cursor runQuery(CharSequence constraint) {
                 return dbHelper.sortByLastname(f);
             }
      }); 
        break;
    case 2:
        ca.setFilterQueryProvider(new FilterQueryProvider() {
             public Cursor runQuery(CharSequence constraint) {
                 return dbHelper.fetchPatientsByName(constraint.toString());
             }
      }); 
        break;
    }
}

DBHelper.class

   public Cursor sortByFirstname(CharSequence inputText) throws SQLException {

      Cursor mCursor = null;
      if (inputText == null  ||  inputText.length () == 0)  {
       mCursor = myDataBase.query(DB_TABLE, new String[] { 
               KEY_ID, KEY_FNAME, KEY_LNAME, KEY_DIAGNOSIS, KEY_LASTFFUP },
         null, null, null, null, null);

      }
      else {
       mCursor = myDataBase.query(true, DB_TABLE, new String[] { 
               KEY_ID, KEY_FNAME, KEY_LNAME, KEY_DIAGNOSIS, KEY_LASTFFUP  },
         KEY_FNAME + " like '%" + inputText + "%'", null,
         null, null, "FirstName asc", null);
      }
      if (mCursor != null) {
       mCursor.moveToFirst();
      }
      return mCursor;

}

public Cursor sortByLastname(CharSequence inputText) throws SQLException {

      Cursor mCursor = null;
      if (inputText == null  ||  inputText.length () == 0)  {
       mCursor = myDataBase.query(DB_TABLE, new String[] { 
               KEY_ID, KEY_FNAME, KEY_LNAME, KEY_DIAGNOSIS, KEY_LASTFFUP },
         null, null, null, null, null);

      }
      else {
       mCursor = myDataBase.query(true, DB_TABLE, new String[] { 
               KEY_ID, KEY_FNAME, KEY_LNAME, KEY_DIAGNOSIS, KEY_LASTFFUP  },
         KEY_FNAME + " like '%" + inputText + "%'", null,
         null, null, "LastName asc", null);
      }
      if (mCursor != null) {
       mCursor.moveToFirst();
      }
      return mCursor;

}

基本上，用户可以通过从微调器中按名字、姓氏或上次检查来对列表进行排序。我试过做上面的代码无济于事。不知道代码有什么问题？还是我错过了什么？有什么想法吗？非常感谢您的帮助。谢谢。

4

2 回答 2

2

试试这样

mCursor = myDataBase.query(DB_TABLE, new String[] { 
               KEY_ID, KEY_FNAME, KEY_LNAME, KEY_DIAGNOSIS, KEY_LASTFFUP },
         null, null, null, null, KEY_LNAME + " ASC");

更多细节在这里

于 2013-09-23T05:03:57.677 回答
0

尝试这个：

mCursor = myDataBase.query(true, DB_TABLE, new String[] { 
               KEY_ID, KEY_FNAME, KEY_LNAME, KEY_DIAGNOSIS, KEY_LASTFFUP  },
         KEY_FNAME + " like '%" + inputText + "%'", null,
         null, null, "FirstName ASC", null);

希望能帮助到你！！

于 2013-09-23T04:56:46.037 回答