我正在编写一个返回动态构造的属性包的 Web API Web 服务。是否有任何有效的序列化程序或如何将动态序列化为 XML 的方法?我试图寻找任何好的建议,但没有找到任何有用的建议。
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4675 次
1 回答
22
We solved it by creating a custom XML formatter.
This isn't an ideal solution but it works.
In the Global.asax
GlobalConfiguration.Configuration.Formatters.Add(new CustomXmlFormatter());
GlobalConfiguration.Configuration.Formatters
.Remove(GlobalConfiguration.Configuration.Formatters.XmlFormatter);
Create a new class called CustomXmlFormatter
using System;
using System.IO;
using System.Net.Http.Formatting;
using System.Net.Http.Headers;
using System.Threading.Tasks;
using Newtonsoft.Json;
namespace EMP.WebServices.api.Formatters
{
public class CustomXmlFormatter : MediaTypeFormatter
{
public CustomXmlFormatter()
{
SupportedMediaTypes.Add(
new MediaTypeHeaderValue("application/xml"));
SupportedMediaTypes.Add(new MediaTypeHeaderValue("text/xml"));
}
public override bool CanReadType(Type type)
{
if (type == (Type)null)
throw new ArgumentNullException("type");
return true;
}
public override bool CanWriteType(Type type)
{
return true;
}
public override Task WriteToStreamAsync(Type type, object value,
Stream writeStream, System.Net.Http.HttpContent content,
System.Net.TransportContext transportContext)
{
return Task.Factory.StartNew(() =>
{
var json = JsonConvert.SerializeObject(value);
var xml = JsonConvert
.DeserializeXmlNode("{\"Root\":" + json + "}", "");
xml.Save(writeStream);
});
}
}
}
于 2013-09-30T01:32:44.223 回答