我有这种对用户进行身份验证的好方法,但是我不知道如何获取请求的状态代码。当我这样做时,我可以清楚地看到它的存在NSLog(@"%@", response);
,但我找不到任何方法来摆脱它。有没有一种方法或者我必须以某种方式自己解析它?
- (BOOL)authenticateUserWithEmail:(NSString *)email password:(NSString *)password
{
NSURL *url = [[NSURL alloc] initWithString:[NSString stringWithFormat:
@"%@/users/sign_in.json?user[email]=%@&user[password]=%@&user[remember_me]=true",
LURL,
email,
password]];
NSMutableURLRequest *urlRequest = [[NSMutableURLRequest alloc] initWithURL:url];
[urlRequest setHTTPMethod:@"POST"];
NSURLResponse *response;
NSError *error;
NSData *responseData = [NSURLConnection sendSynchronousRequest:urlRequest returningResponse:&response error:&error];
NSLog(@"Response: %@", [[NSString alloc] initWithData:responseData encoding:NSASCIIStringEncoding] );
NSLog(@"Response Meta: %@", response);
return (error == NULL);
}