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我在 Raspberry Pi 上运行 python 脚本，我使用 4 个 gpio 引脚，3 个作为输出，1 个作为输入。当输入设置为低时，它会激活一个程序，即输出都在不同时间打开和关闭，并使用 pygame.mixer 播放声音效果。我开始遇到一些问题，即输入不再激活程序。当我进一步查看它时，我发现它只能工作 120 次，然后输入将不再激活程序，并且我不会收到任何错误消息。我绝不是 python 编码方面的专家，所以我的代码可能看起来很乱。这是代码。

    import RPi.GPIO as GPIO
    import sys
    import time
    import pygame
    import os
    from array import *

    print "loading program"
    GPIO.setmode(GPIO.BCM)
    GpioPinsOut=[4,17,27]
    for a in range (0, len(GpioPinsOut)):
        GPIO.setup(GpioPinsOut[a], GPIO.OUT)
    GpioPinsIn=[7,]
    for y in range (0, len(GpioPinsIn)):
        GPIO.setup(GpioPinsIn[y], GPIO.IN)
    start=0
    prevTriggered=0
    triggered=0
    elapsed=0
    vars=[0,]
    inVars=[0]
    prevInVars=[5,5]
    sceneNames=["Night"]
    onoffVar=  [1, 0]
    onoffVar2= ["On", "Off"]
    outputNamesFinal=['output1','output2','output3']
    outputNames= [[['output1','output2','output3'],['output1','output2','output3','reset']]]
    outputs=     [[[4        ,17       ,27       ],[4        ,17       ,27       ,'reset']]]
    times=       [[[0.0      ,0.0      ,0.0      ],[11.7     ,18.0     ,18.0     ,18.0   ]]]
    printGpioVar=[[[0        ,0        ,0        ],[0        ,0        ,0        ,0      ]]]
    outputsAlwaysOn=[[]]
    for va in range (0, len(GpioPinsOut)):
        GPIO.output(GpioPinsOut[va], False)
    for za in range (0, len(outputsAlwaysOn[0])):
        GPIO.output(outputsAlwaysOn[0][za], True)               
    effects=[[],[]]
    effectslocations=[['/root/audio/soundeffect.wav']]
    pygame.mixer.init(44100, -16, 2, 2048)
    for ba in range (0, len(effectslocations)):
        for bb in range (0, len(effectslocations[ba])):
            effectsVar = pygame.mixer.Sound(effectslocations[ba][bb])
            effects[ba].append(effectsVar)
    effectsNumbers=[[0  ]]
    effectsTimes=  [[0.0]]
    sfxVAR = 0
    numberOfTimes=0
    print "program ready"
    try:
        while True:
            for z in range (0, len(GpioPinsIn)):
                if GPIO.input(GpioPinsIn[z]) == False:
                    inVars[z]=0
                else:
                    inVars[z]=1
            if inVars[0] == 0:
                triggered = 1

            if triggered == 1:
                if prevTriggered != triggered:
                    print "Trigger Activated"
                    if start == 0:
                        print "Start Time Activated"
                        numberOfTimes+=1
                        print numberOfTimes
                        start = time.clock()
                elapsed = time.clock() - start
                for g in range(0, len(effectsTimes[0])):
                    if elapsed >= effectsTimes[0][g]:
                        if sfxVAR == 0:
                            effects[0][effectsNumbers[0][g]].play()
                            sfxVAR = 1

                for c in range (0, len(times[0])):
                    for d in range (0, len(times[0][c])):
                        if elapsed >= times[0][c][d]:
                            if outputs[0][c][d] == "reset":
                                print "done with %s procedures"%sceneNames[0]
                                for e in range (0, len(printGpioVar[0])):
                                    for f in range (0, len(printGpioVar[0][e])):
                                        printGpioVar[0][e][f]=0 
                                start=0
                                prevTriggered=0
                                sfxVAR=0
                                triggered=0

                            else:
                                if printGpioVar[0][c][d]==0:
                                    GPIO.output(outputs[0][c][d], onoffVar[c])
                                    print "Turned %s %s"%(onoffVar2[c], outputNames[0][c][d])
                                    printGpioVar[0][c][d]=1

                prevTriggered = triggered
            for g in range (0, len(inVars)):
                prevInVars[g]=inVars[g]
    except KeyboardInterrupt:
        GPIO.cleanup()
        sys.exit()
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1 回答 1

0

您必须处理应用程序循环中的事件。pygame.event.get()分别见pygame.event.pump()：

对于游戏的每一帧，您都需要对事件队列进行某种调用。这确保您的程序可以在内部与操作系统的其余部分进行交互。

try:
    while True:
        pygame.event.pump()

        # [...]
于 2020-12-21T16:44:37.530 回答