1

当我运行此代码时，它给了我IllegalArgumentException，然后执行了整个代码，但是线程 t 的名称仅为默认名称，而不是根据代码标记。

可能是什么原因？

    Exception in thread "main" java.lang.IllegalArgumentException
        at java.lang.Thread.setPriority(Unknown Source)
        at Threads.CurrentThreadImpl.main(CurrentThreadImpl.java:11)
    value of I is : 0and the thread name is : Thread-0
    value of I is : 1and the thread name is : Thread-0
    value of I is : 2and the thread name is : Thread-0
    value of I is : 3and the thread name is : Thread-0
    value of I is : 0and the thread name is : Thread-1
    value of I is : 1and the thread name is : Thread-1
    value of I is : 2and the thread name is : Thread-1
    value of I is : 3and the thread name is : Thread-1

    public class CreateThread implements Runnable{

    public void run(){
        for(int i = 0; i<4; i++){
            System.out.println("value of I is : "+ i + "and the thread name is : "+ Thread.currentThread().getName());
        }
    }
}

    public class CurrentThreadImpl {

    public static void main(String[] args) {
        CreateThread runnableObj = new CreateThread();
        Thread thread = new Thread(runnableObj);
        Thread t = new Thread(runnableObj);
        thread.start();
        t.start();
        thread.setPriority(0);
        t.setPriority(10);
        t.setName("Mark");
    }

}
4

2 回答 2

8

见线程#setPriority：

IllegalArgumentException - 如果优先级不在 MIN_PRIORITY到MAX_PRIORITY范围内。

MIN_PRIORITY是 1，而不是 0：

在此处输入图像描述

于 2013-09-22T13:06:57.863 回答
4

优先级从 1 到 10。

Thread.MIN_PRIORITY (1)
Thread.NORM_PRIORITY (5)
Thread.MAX_PRORITY (10)
于 2013-09-22T13:08:09.497 回答