-1

我想制作一个函数来判断来自 url 的数字是奇数还是偶数。以下是关于法官的代码：

#!/usr/bin/env python
#-*- coding:utf-8 -*-

from django.http import HttpResponse,Http404
import datetime

def judge(reqest, number):
    try:
        number = int(number)
    except ValueError:
        raise Http404() 
    if number % 2 == 0:
        html = "<html><body>%d is even!</body></html>" % (number)
    else:
        html = "<html><body>%d is odd!</body></html>" % (number)
    return HttpResponse(html)

现在，我被困在了url.py，我不知道这样的编辑是否会起作用：

from django.conf.urls.defaults import *
from views import *

urlpatterns = patterns('',
   #(r'^$', time_now),
   (r'^number/(.+)$', judge), # we just want the number in the url, not more or less
)

但我也想处理空输入，但是"Nothing input"每次我尝试这个时页面都会给出：

def judge(reqest, number):
    if number is None:
        html = "nothing input!"
        return HttpResponse(html)
    try:
        number = int(number)
    except ValueError:
        raise Http404() 
    if number % 2 == 0:
        html = "<html><body>%d is even!</body></html>" % (number)
    else:
        html = "<html><body>%d is odd!</body></html>" % (number)
    return HttpResponse(html)

我怎样才能解决这个问题？

4

1 回答 1

1

像这样定义两个url

网址.py

from views import *

urlpatterns = patterns('',
   #(r'^$', time_now),
   (r'^number/(.+)/$', judge),
   (r'^number/$', judge),
)

设置默认值

视图.py

def judge(reqest, number=None):
    ...
于 2013-09-22T12:07:06.873 回答