尝试这个

<select name="the_name">
<?php foreach($array as $option) : ?>
        <option value="<?php echo $option['Name']; ?>"><?php echo $option['Name']; ?></option>
<?php endforeach; ?>
</select>

执行查询后，使用while循环添加选项以选择

$query = $mysqli->query("select distinct bname as Name from kjv limit 1"); ?>

<select>
    <?php while($option = $query->fetch_object()){ ?>
        <option><?php echo $option->Name; ?></option>
    <?php } ?>
</select>

不确定 array_pop 在代码中做了什么

正如 TIM WAX 所说，这是解决方案

$query = $mysqli->query("select distinct bname as Name from kjv limit 1"); ?>

<select>
    <?php while($option = $query->fetch_object()){ ?>
        <option><?php echo $option->Name; ?></option>
    <?php } ?>
</select>

这是我的..我是初学者，但它对我有用，

    $query = $mysqli->query("SELECT * FROM  `student_type_db`"); //table of student type

    echo "<select>";
    while($row = $query->fetch_array()){
         echo "<option>";
         echo $row['student_type'] . " - " . $row['student_description'];
         echo "</option>"; 
    }
    echo "</select>";

   // student type = 1 | student description = regular
   // output : 1 - regular

<select name="the_name">
<?php foreach($array as $option) : ?>
        <option value="<?php echo $option->Name; ?>"></option>
<?php endforeach; ?>
</select>

您以一种也<select>一次又一次地创建标签的方式结束了循环。更改它并重试。我不太了解，.php但显示下拉框可能是个问题。