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我有两个变量和一个试图传递给 PHP 页面的数组。不幸的是,虽然我做了一些搜索,但我无法成功传递我的数组。变量工作正常。有什么帮助吗?

这是我的 JQuery 代码:

$('#submit').click(function() {
        $.post('process.php', {primary: $prim, secondary: $seco, not: $not}, 
        function(data) {
            //alert("Data Loaded: " + data);
            $("#error").html(data);
        });
});

在哪里

$not = {1,2,3};

进程.php

<?php
    require("common.php");
    $primary = $_POST['primary'];
    $secondary = $_POST['secondary'];
    $not = $_POST['not'];
    //echo("primary: "+$primary+", secondary: "+$secondary+", not: "+$not);
    echo($primary);
?>

错误信息

Notice: Undefined index: not in C:\wamp\www\process.php on line 5

刚刚意识到可能是因为`not`是php中的关键字

不,不是因为那个

4

1 回答 1

0

In Your JQuery use join(",")

$('#submit').click(function() {
        $.post('process.php', {primary: $prim, secondary: $seco, not: $not.join(",")}, 
        function(data) {
            //alert("Data Loaded: " + data);
            $("#error").html(data);
        });
});

And in your PHP use explode() function to convert from string to array

<?php
    require("common.php");
    $primary = $_POST['primary'];
    $secondary = $_POST['secondary'];
    $not =  explode(',', $_POST['not']) ;
    //echo("primary: "+$primary+", secondary: "+$secondary+", not: "+$not);
    echo($primary);
?>
于 2013-09-21T18:39:00.753 回答