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到目前为止的应用程序的简要说明:

用户看到一个包含单词的TextView 。用户将单击将触发 Speech To Text API的ImageButton并说出TextView上给出的单词。如果 Speech To Text 中的文本与TextView中的文本匹配,则TextView会将文本更改为“正确!” 等等

问题是比较字符串文本值。TextView有“你好” 。当我说“Hello”时,SpeechToText api 返回“Hello”,但文本值被认为是不同的。

activity_main.xml

<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
    xmlns:tools="http://schemas.android.com/tools"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    android:paddingBottom="@dimen/activity_vertical_margin"
    android:paddingLeft="@dimen/activity_horizontal_margin"
    android:paddingRight="@dimen/activity_horizontal_margin"
    android:paddingTop="@dimen/activity_vertical_margin"
    tools:context=".Main"
    android:orientation="vertical" >
    <ImageButton
        android:id="@+id/btnSpeak"
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:layout_margin="10dp"
        android:layout_marginRight="10dp"
        android:layout_marginTop="10dp"
        android:src="@android:drawable/ic_btn_speak_now" />
    <TextView
        android:id="@+id/inputText"
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:layout_marginLeft="10dp"
        android:layout_marginRight="10dp"
        android:layout_marginTop="10dp"
        android:textAppearance="?android:attr/textAppearanceLarge" 
        android:layout_gravity="center"/>
    <TextView
        android:id="@+id/givenText"
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:text="@string/text"
        android:layout_gravity="center" />
</LinearLayout>

主.Java

package com.example.speechtotext;
import java.util.ArrayList;
import android.app.Activity;
import android.content.ActivityNotFoundException;
import android.content.Intent;
import android.os.Bundle;
import android.speech.RecognizerIntent;
import android.view.Menu;
import android.view.View;
import android.widget.ImageButton;
import android.widget.TextView;
import android.widget.Toast;

public class Main extends Activity {
    protected static final int RESULT_SPEECH = 1;
    private ImageButton btnSpeak;
    private TextView inputText;
    private TextView givenText;
    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        inputText = (TextView)findViewById(R.id.inputText);
        givenText = (TextView)findViewById(R.id.givenText);
        btnSpeak = (ImageButton)findViewById(R.id.btnSpeak);
        btnSpeak.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                // TODO Auto-generated method stub
                Intent intent = new Intent(RecognizerIntent.ACTION_RECOGNIZE_SPEECH);
                intent.putExtra(RecognizerIntent.EXTRA_LANGUAGE_MODEL, "en-US");
                try{
                    startActivityForResult(intent, RESULT_SPEECH);
                    inputText.setText("");
                }catch(ActivityNotFoundException a) { 
                    Toast t = Toast.makeText(getApplicationContext(),
                            "your device does not support Speech to Text!",Toast.LENGTH_SHORT);
                    t.show();
                }
            }
        });
    }

    @Override
    public boolean onCreateOptionsMenu(Menu menu) {
        // Inflate the menu; this adds items to the action bar if it is present.
        getMenuInflater().inflate(R.menu.main, menu);
        return true;
    }

    @Override
    protected void onActivityResult(int requestCode, int resultCode, Intent data) {
        super.onActivityResult(requestCode, resultCode, data);
        switch (requestCode) {
        case RESULT_SPEECH: {
            if (resultCode == RESULT_OK && null != data) {

                ArrayList<String> text = data
                        .getStringArrayListExtra(RecognizerIntent.EXTRA_RESULTS);

                inputText.setText(text.get(0));

                if(givenText.getText().toString().equals(inputText.getText().toString())){
                    givenText.setText("Correct!");
                }
                else{
                    givenText.setText("Incorrect!");
                }
            }
            break;
        }
        }
    }
}

有任何想法吗?

4

1 回答 1

1

通过更改代码中的一行可以轻松解决您面临的问题,即:

if(givenText.getText().toString().equals(inputText.getText().toString())){

将其更改为:

if(givenText.getText().toString().equalsIgnoreCase(inputText.getText().toString())){

此外,我在开发类似应用程序时所做的一般性观察,我注意到语音识别 API 并不完美,除非您/您的用户的口音与 API 训练的口音相匹配,否则无法正常工作上。因此,为了解决这个问题,您应该考虑查看返回的字符串的 ArrayList 并检查所有字符串,以查看其中是否有任何一个与您向用户显示的文本匹配。

于 2013-09-21T05:18:45.897 回答