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我需要将大量结构化文本格式的文件转换为 excel（csv 可以），以便能够将它们与我拥有的其他一些数据合并。以下是文本示例：

   FILER:

    COMPANY DATA:   
        COMPANY CONFORMED NAME:         NORTHQUEST CAPITAL FUND  INC
        CENTRAL INDEX KEY:          0001142728
        IRS NUMBER:             223772454
        STATE OF INCORPORATION:         NJ
        FISCAL YEAR END:            1231

    FILING VALUES:
        FORM TYPE:      NSAR-A
        SEC ACT:        1940 Act
        SEC FILE NUMBER:    811-10419
        FILM NUMBER:        03805344

    BUSINESS ADDRESS:   
        STREET 1:       16 RIMWOOD LANE
        CITY:           COLTS NECK
        STATE:          NJ
        ZIP:            07722
        BUSINESS PHONE:     7328423504

    FORMER COMPANY: 
        FORMER CONFORMED NAME:  NORTHPOINT CAPITAL FUND INC
        DATE OF NAME CHANGE:    20010615
</SEC-HEADER>
<DOCUMENT>
<TYPE>NSAR-A
<SEQUENCE>1
<FILENAME>answer.fil
<DESCRIPTION>ANSWER.FIL
<TEXT>
<PAGE>      PAGE  1
000 A000000 06/30/2003
000 C000000 0001142728
000 D000000 N
000 E000000 NF
000 F000000 Y
000 G000000 N
000 H000000 N
000 I000000 6.1
000 J000000 A
001 A000000 NORTHQUEST CAPITAL FUND, INC.
001 B000000 811-10493
001 C000000 7328921057
002 A000000 16 RIMWOOD LANE
002 B000000 COLTS NECK
002 C000000 NJ
002 D010000 07722
003  000000 N
004  000000 N
005  000000 N
006  000000 N
007 A000000 N
007 B000000  0
007 C010100  1
007 C010200  2
007 C010300  3
007 C010400  4
007 C010500  5
007 C010600  6
007 C010700  7
007 C010800  8
007 C010900  9
007 C011000 10
008 A000001 EMERALD RESEARCH CORP.
008 B000001 A
008 C000001 801-60455
008 D010001 BRICK
008 D020001 NJ
008 D030001 08724
013 A000001 SANVILLE & COMPANY
013 B010001 ABINGTON
013 B020001 PA
013 B030001 19001
015 A000001 FLEET BANK
015 B000001 C
015 C010001 POINT PLEASANT BEACH
015 C020001 NJ
015 C030001 08742
015 E030001 X
018  000000 Y
019 A000000 N
019 B000000    0
<PAGE>      PAGE  2
020 A000001 SCHWAB
020 B000001 94-1737782
020 C000001      0
020 A000002 BESTVEST BROOKERAGE
020 B000002 23-1452837
020 C000002      0

它继续到相同结构的第 8 页。关于公司名称的信息应该放在相关的列中，其余的应该像前两个值是列名，第三个值是行的值。

我试图用 pyparsing 解决它，但未能成功。对该方法的任何评论都会有所帮助。

4

1 回答 1

2

您描述它的方式，这些就像每个文件的键：值对。我会像这样处理解析部分：

import sys
import re
import csv

colonseperated = re.compile(' *(.+) *: *(.+) *')
fixedfields = re.compile('(\d{3} \w{7}) +(.*)')

matchers = [colonseperated, fixedfields]

outfile = csv.writer(open('out.csv', 'w'))

outfile.writerow(['Filename', 'Key', 'Value'])
for filename in sys.argv[1:]:   
    for line in open(filename):
        line = line.strip()
        for matcher in matchers:
            match = matcher.match(line)
            if match:
                outfile.writerow([filename] + list(match.groups()))

您可以将其称为类似的名称，并使用或任何您的文件名约定来parser.py调用它。python parser.py *.infile它将创建一个包含三列的 csv 文件：文件名、键和值。您可以在 excel 中打开它，然后使用数据透视表将值转换为正确的格式。

或者，您可以使用这个：

import csv

headers = []
rows = {}
filenames = []

outfile = csv.writer(open('flat.csv', 'w'))
infile = csv.reader(open('out.csv'))
infile.next()

for filename, key, value in infile:
    if not filename in rows:
        rows[filename] = {}
        filenames.append(filename)
    if key not in headers:
        headers.append(key)
    rows[filename][key] = value

outfile.writerow(headers)
for filename in filenames:
    outfile.writerow([rows[filename].get(header, '') for header in headers])
于 2013-09-21T09:38:05.083 回答