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任务是获取有超过 2 个不同特殊代码的订单代码列表，现在我已经有了这个查询

SELECT
    o.id        AS iOrderId,
    o.code          AS sOrderCode,
    oa.pnr          AS sSpecialCode
FROM
    order_air AS oa
JOIN
    orders AS o ON 1
        AND oa.order_id = o.id
WHERE 1 
    AND o.status = 11
    AND oa.issued = 1
    AND oa.change_status != 0
    AND oa.issued_date BETWEEN NOW() - INTERVAL 12 MONTH AND NOW()
GROUP BY o.id
HAVING COUNT(*) >= 2
LIMIT 20

它还给我

在此处输入图像描述

一切都很好，但是这个查询不检查不同的特殊代码，只是返回所有超过 2 个特殊代码的订单代码。我也尝试过查看 IF 以保存以前的 orderid，然后通过它进行检查，但我不知道如何将以前的 id 存储到 @prev 之类的东西中，所以这对我没有帮助，任何想法如何正确过滤这个队列?

4

2 回答 2

1

我认为这就是你想要做的。

SELECT
    o.id        AS iOrderId,
    o.code      AS sOrderCode
FROM
    orders AS o
JOIN
    (SELECT order_id, COUNT(DISTINCT pnr) AS cnt
     FROM order_air
     WHERE issued = 1
       AND change_status != 0
       AND issued_date BETWEEN NOW() - INTERVAL 12 MONTH AND NOW()
     GROUP BY order_id) oa_count
ON o.id = oa_count.order_id

WHERE oa_count.cnt >= 2 
  AND o.status = 11

LIMIT 20
于 2013-09-20T08:57:47.437 回答
0 
JOIN
orders AS o ON 1
    AND oa.order_id = o.id
    AND something < something else
于 2013-09-20T08:52:14.420 回答