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好的，这对谷歌来说是一个难题。我想要的是一旦用户在库存数组中输入 10 个项目，我希望它清除控制台并讲述一个故事。我尝试过，但无论数组中有多少项目，它都会显示故事，因为我将数组定义为最大 10。我还试图找到一种方法来交换数组中的项目。我的意思是我希望控制台询问用户是否愿意将 {item which is already in the array} 换成 {item2} y 或 n？

问题是它不显示项目名称只是在故事示例中输出的数组中的位置。显示“你想用 1 交换附魔剑吗”。然后，如果您点击是，它不会将其添加到数组中。无论如何它也绕过了我的谢谢

  void tellStory(InventoryRecord list[], int& size)
{
    int numOfRecs = size;
    int pos = rand()%numOfRecs; //Generate a random position of the item
    //Generate item to trade, I'll refer to it as "Item
    int TRADE_CHANCE = 0;
    const string str = "Enchanted Sword";
    InventoryRecord recList[MAX_SIZE];
    if (numOfRecs == MAX_SIZE) {
        system("cls");
        cout << "So your ready to begin your quest!" << endl << endl;
        cout << "Before you begin I would like the opportunity to trade you a rare item!" << endl << endl;
        cout << "Would you like to trade" << pos <<  "for" << str  << "?" << endl << endl;
        cout << "Yes or No? ";
        cin >> choice;
      if (toupper(choice) == 'Y') 
    (rand()%100 < TRADE_CHANCE); 
   (recList[pos], str);//Here add the trading stuff, which is some text, user input(y/n) and replacing realist[pos] = Item, etc
     }
     else {
         cout << "Thanks anyways!" << endl << endl;
   system("pause");
  }
  system("cls");
    }
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1 回答 1

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问题是您没有在任何地方检查库存是否已满。您可能想要更换

案例“A”：addData（recList，numOfRecs）；休息;

如果你只想讲一个故事

case 'A':
    if (numOfRecs == MAX_SIZE-1) {
      addData(recList, numOfRecs);
      //TELL STROY HERE 
    } else{
      addData(recList, numOfRecs);//If you want to tell a story only once
    }
    break;

如果你想随时讲故事

case 'T': //TEll story
    if (numOfRecs == MAX_SIZE) {
      //TELL STORY HERE 
    } 
break;

或者，尽管这很烦人，但在每次行动后，检查库存中是否有 10 件物品并显示故事

现在进行交易，假设您希望他们交易他们拥有的物品，对于您要生成的随机物品使用： pos = rand()%numOfRecs; //生成项目的随机位置现在如果你想生成一个“随机”的交易建议：

if (rand()%100 < TRADE_CHANCE) {
    int pos = rand()%numOfRecs; //Generate a random position of the item
    //Generate item to trade, I'll refer to it as "Item"
    SuggestTrade(recList[pos], Item);//Here add the trading stuff, which is some text, user input(y/n) and replacing realist[pos] = Item, etc
}

如果您要交易的项目，它实际上是同一数组中的头寸交换：

int pos = rand()%numOfRecs; //Generate a random position of the item
int pos2;
do {
    pos2 = rand()%numOfRecs; //Generate a random position of the item
}while (pos2 == pos);
//Actually "swapping"
InventoryRecord tmp = recList[pos];
recList[pos] = recList[pos2];
recList[pos2] = tmp;

希望能帮助到你！

于 2013-09-20T01:00:57.053 回答