1

我正在创建一个电影数据库，我想我已经完成了它的设计，但是我的结果并没有像我希望的那样回来。我现在数据库中只有 2 部电影的详细信息。我试图让它停止显示重复的信息。

你能看一下并提供反馈吗？

我在这里先向您的帮助表示感谢。

/*
 Navicat MySQL Data Transfer

 Source Server         : localhost
 Source Server Version : 50525
 Source Host           : localhost
 Source Database       : MovieDB

 Target Server Version : 50525
 File Encoding         : utf-8

 Date: 09/12/2013 22:06:21 PM
*/

SET NAMES utf8;
SET FOREIGN_KEY_CHECKS = 0;

-- ----------------------------
--  Table structure for `FORMAT`
-- ----------------------------
DROP TABLE IF EXISTS `FORMAT`;
CREATE TABLE `FORMAT` (
  `ID` int(10) NOT NULL AUTO_INCREMENT,
  `Formats` varchar(10) NOT NULL DEFAULT '',
  PRIMARY KEY (`ID`)
) ENGINE=InnoDB AUTO_INCREMENT=7 DEFAULT CHARSET=utf8;

-- ----------------------------
--  Table structure for `FORMAT_ID`
-- ----------------------------
DROP TABLE IF EXISTS `FORMAT_ID`;
CREATE TABLE `FORMAT_ID` (
  `MovieID` int(11) NOT NULL DEFAULT '0',
  `FormatID` int(11) NOT NULL DEFAULT '0',
  `Num_Discs` int(128) DEFAULT NULL,
  `Locations` varchar(128) DEFAULT NULL,
  PRIMARY KEY (`MovieID`,`FormatID`),
  KEY `FormatID` (`FormatID`),
  CONSTRAINT `FORMAT_ID_ibfk_1` FOREIGN KEY (`MovieID`) REFERENCES `MOVIE` (`ID`),
  CONSTRAINT `FORMAT_ID_ibfk_2` FOREIGN KEY (`FormatID`) REFERENCES `FORMAT` (`ID`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;

-- ----------------------------
--  Table structure for `GENRE`
-- ----------------------------
DROP TABLE IF EXISTS `GENRE`;
CREATE TABLE `GENRE` (
  `ID` int(11) NOT NULL AUTO_INCREMENT,
  `Genres` varchar(50) NOT NULL DEFAULT '',
  `Descriptions` varchar(128) DEFAULT NULL,
  PRIMARY KEY (`ID`)
) ENGINE=InnoDB AUTO_INCREMENT=39 DEFAULT CHARSET=utf8;

-- ----------------------------
--  Table structure for `GENRE_ID`
-- ----------------------------
DROP TABLE IF EXISTS `GENRE_ID`;
CREATE TABLE `GENRE_ID` (
  `MovieID` int(11) NOT NULL DEFAULT '0',
  `GenreID` int(11) NOT NULL DEFAULT '0',
  PRIMARY KEY (`MovieID`,`GenreID`),
  KEY `GenreID` (`GenreID`),
  CONSTRAINT `GENRE_ID_ibfk_2` FOREIGN KEY (`GenreID`) REFERENCES `GENRE` (`ID`),
  CONSTRAINT `GENRE_ID_ibfk_1` FOREIGN KEY (`MovieID`) REFERENCES `MOVIE` (`ID`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;

-- ----------------------------
--  Table structure for `MOVIE`
-- ----------------------------
DROP TABLE IF EXISTS `MOVIE`;
CREATE TABLE `MOVIE` (
  `ID` int(11) NOT NULL AUTO_INCREMENT,
  `Titles` varchar(128) NOT NULL DEFAULT '',
  `Alt_Titles` varchar(128) DEFAULT NULL,
  `Types` varchar(10) NOT NULL DEFAULT '',
  `Synopsis` varchar(128) DEFAULT NULL,
  `Images` varchar(128) DEFAULT NULL,
  `Num_Eps` int(10) DEFAULT '0',
  `Catagories` varchar(50) NOT NULL DEFAULT '',
  `Duration` time DEFAULT NULL,
  PRIMARY KEY (`ID`)
) ENGINE=InnoDB AUTO_INCREMENT=3 DEFAULT CHARSET=utf8;

-- ----------------------------
--  Table structure for `RENT`
-- ----------------------------
DROP TABLE IF EXISTS `RENT`;
CREATE TABLE `RENT` (
  `MovieID` int(11) NOT NULL DEFAULT '0',
  `Rents` varchar(3) NOT NULL DEFAULT '',
  `Who` varchar(128) NOT NULL DEFAULT '',
  `Note` varchar(128) DEFAULT NULL,
  PRIMARY KEY (`MovieID`,`Rents`,`Who`),
  CONSTRAINT `RENT_ibfk_1` FOREIGN KEY (`MovieID`) REFERENCES `MOVIE` (`ID`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;

SET FOREIGN_KEY_CHECKS = 1;

sql：

select distinct Titles, Types, Num_Eps, Catagories, Duration, Formats, Num_Discs, Genres
from MOVIE, FORMAT, FORMAT_ID, GENRE, GENRE_ID
where MOVIE.ID=GENRE_ID.MovieID
AND GENRE_ID.GenreID=GENRE.ID
and MOVIE.ID=FORMAT_ID.MovieID
AND FORMAT_ID.FormatID=FORMAT.ID
order by Titles;

这是我的结果：

Titles,Types,Num_Eps,Catagories,Duration,Formats,Num_Discs,Genres
Ghost in the Shell,Movie,1,Anime,01:23:00,DVD,1,Mecha
Ghost in the Shell,Movie,1,Anime,01:23:00,DVD,1,Police
Ghost in the Shell,Movie,1,Anime,01:23:00,DVD,1,Psychological
Ghost in the Shell,Movie,1,Anime,01:23:00,DVD,1,Sci-Fi
Ghost in the Shell,Movie,1,Anime,01:23:00,DVD,1,Cyberpunk
Ghost in the Shell,Movie,1,Anime,01:23:00,Bluray,1,Mecha
Ghost in the Shell,Movie,1,Anime,01:23:00,Bluray,1,Police
Ghost in the Shell,Movie,1,Anime,01:23:00,Bluray,1,Psychological
Ghost in the Shell,Movie,1,Anime,01:23:00,Bluray,1,Sci-Fi
Ghost in the Shell,Movie,1,Anime,01:23:00,Bluray,1,Cyberpunk
Summer Wars,Movie,1,Anime,01:54:00,DVD,1,Comedy
Summer Wars,Movie,1,Anime,01:54:00,DVD,1,Sci-Fi
Summer Wars,Movie,1,Anime,01:54:00,HD,,Comedy
Summer Wars,Movie,1,Anime,01:54:00,HD,,Sci-Fi
4

3 回答 3

1

几点。我会使用完全连接语法，

FROM MOVIE JOIN GENRE ON MOVIE.ID=GENRE_ID.MovieID

而不是您现在拥有的 where 子句。

然后你可能想尝试 GROUP_CONCAT(expr) 将你的流派连接成一行，例如。机甲、警察、心理等……

于 2013-09-19T21:58:57.547 回答
0

更新：感谢 Vulcronos，如果我使用

类型：

select distinct Titles, Types, Num_Eps, Catagories, Duration, Genres 
FROM MOVIE JOIN GENRE_ID ON MOVIE.ID=GENRE_ID.MovieID, GENRE 
where GENRE_ID.GENREID=GENRE.ID 
order by Titles;

格式：

select distinct Titles, Types, Num_Eps, Catagories, Duration, Formats, Num_Discs, Locations 
FROM MOVIE JOIN FORMAT_ID ON MOVIE.ID=FORMAT_ID.MovieID, FORMAT 
where FORMAT_ID.FORMATID=FORMAT.ID 
order by Titles;

有没有办法将两者结合起来？

所以我会得到这样的东西：

Ghost in the Shell,Movie,1,Anime,01:23:00,DVD,1,Mecha
Ghost in the Shell,Movie,1,Anime,01:23:00,DVD,1,Police
Ghost in the Shell,Movie,1,Anime,01:23:00,DVD,1,Psychological
Ghost in the Shell,Movie,1,Anime,01:23:00,DVD,1,Sci-Fi
Ghost in the Shell,Movie,1,Anime,01:23:00,Bluray,1,Cyberpunk
Summer Wars,Movie,1,Anime,01:54:00,DVD,1,Comedy
Summer Wars,Movie,1,Anime,01:54:00,HD,,Sci-Fi

它会在哪里列出一次流派和一次格式。当然，对于多种流派，除非有办法解决该问题，否则格式会重复出现，但至少会显示所有格式一次以及流派一次。

谢谢您的帮助。

于 2013-09-26T19:45:43.243 回答
0

可能没有人再看这个帖子了，但我想让未来的观点和帮助我的人在问题中找到我想要的东西。

select DISTINCT m.Title, 
            group_concat(DISTINCT g.Genre) as Genres, 
            group_concat(DISTINCT f.Format) as Formats
from MOVIES m 
left join MOVIEGENRES mg on m.Code=mg.MovieCode
left join GENRES g on mg.GenCode=g.Code
left join MOVIEFORMATS mf on m.Code=mf.MovieCode
left join FORMATS f on mf.FormCode=f.Code
group by m.Code;
于 2014-08-29T01:16:17.670 回答