0

我有一个任务,我必须显示一个类的所有属性。

我的问题是我可以做些什么来使代码工作而不必向 person 对象添加额外的属性?

我让代码可以工作,但显然我不应该对原始的person类进行任何更改。这是:

class person
{
String firstName;
String lastName;
int age;

person(String informedFirstName, String informedLastName, int informedAge)
{
    firstName = informedFirstName;
    lastName = informedLastName;
    age = informedAge;
}

String whatIsUp()
{
 return "undetermined";
}
String getName()
{
    return firstName +" "+lastName;
}
String getAge()
{
    String str = String.valueOf(age);
    return str;
}

String getInfo()
{
    return ("Name = "+ getName() + " age="+ getAge());
}
}

我拥有的工作代码是:

应用类

class app

{
  public static void main(String[] args)
 {
student st1 = new student("Zack","Mills",21,".....");
professor p1 = new professor("Fred","Fonseca",44,".....");
TA ta1 = new TA("Paris","Hilton",20,"......");
System.out.println(st1.getInfo());
System.out.println(p1.getInfo());
System.out.println(ta1.getInfo());
 }
}

人类:

class person
{
String firstName;
String lastName;
int age;
    String status;

person(String informedFirstName, String informedLastName, 
int informedAge, String informedStatus) //< ---- added attribute informedStatus
{
    firstName = informedFirstName;
    lastName = informedLastName;
    age = informedAge;
            status = informedStatus;
}

String whatIsUp()
{
 return "undetermined";
}
String getName()
{
    return firstName +" "+lastName;
}
String getAge()
{
    String str = String.valueOf(age);
    return str;
}
    String getStatus(){
        return status;
    }

String getInfo()
{
    return ("Name = "+ getName() + " age="+ getAge()) + getStatus();
}

}

学生班级:

class student extends person
{
String status;
student(String informedFirstName, String informedLastName, int informedAge, String informedStatus)
{
    super(informedFirstName, informedLastName, informedAge, informedStatus);
    if (age <= 25) status = informedStatus = "Traditional";
    else status = informedStatus = "Non-Traditional";
}

String whatIsUp()
{
 int n = 0;
 String b = "..."; 
 n = (int) (Math.random()*2);
 if (n == 0) b = "reading";
 if (n == 1) b = "talking";  
 return b;
}
String getStatus()
{
    return " Status = " + status;
}
}

教授班:

class professor extends person
{
String status;
professor(String informedFirstName, String informedLastName, int informedAge, String informedStatus)
{
    super(informedFirstName, informedLastName, informedAge, informedStatus);
    status = informedStatus = "Computer Science";
}

String whatIsUp()
{
 int n = 0;
 String b = "..."; 
 n = (int) (Math.random()*2);
 if (n == 0) b = "reading";
 if (n == 1) b = "talking";  
 return b;
}
String getStatus()
{
    return " Degree = " + status;
}
}

TA类:

class TA extends person
{
String status;
TA (String informedFirstName, String informedLastName, int informedAge, String informedStatus)
{
    super(informedFirstName, informedLastName, informedAge, informedStatus);
    status = informedStatus = "Excellent";
}

String whatIsUp()
{
 int n = 0;
 String b = "..."; 
 n = (int) (Math.random()*2);
 if (n == 0) b = "reading";
 if (n == 1) b = "talking";  
 return b;
}
String getStatus()
{
    return " Communication Skills = " + status;
}
 }

抱歉所有代码,非常感谢任何帮助。

4

2 回答 2

0

我不确定在人员类中再添加一个属性有什么问题。但是,如果您不想触摸它,我会建议您另一种选择。

创建一个扩展人的类 personExtension。将新的状态属性添加到该类。现在为 TA、学生和教授扩展新的 personExtension 类。

class personExtension extends person
{
    String status;

personExtension(String informedFirstName, String informedLastName, int informedAge, String informedStatus)
{
    super(informedFirstName,informedLastName,informedAge);
    status = informedStatus;
}
}
于 2013-09-19T21:02:15.490 回答
0

实际上,您可以通过从studen扩展创建类person并在新类中具有新属性来完成这一切status 。这样做你就有了一个类,它具有person包括新添加的所有属性。

只需status从 person 中删除属性并根据需要保持不变。

在构造函数中student传递person使用super关键字的属性。

student(String informedFirstName, String informedLastName, int informedAge,
        String informedStatus)
{
    super(informedFirstName, informedLastName, informedAge);
    if (age <= 25) status = informedStatus = "Traditional";
    else status = informedStatus = "Non-Traditional";
}

类的对象student将使您可以访问所有属性

student s = new student("John", "Doe", 25, "some status");

只是一个补充,请尽量尊重java命名约定,类名应该以大写字母开头。

编辑

getInfo()返回包含状态的字符串,您必须在子类中覆盖该方法,student并再次使用super关键字调用getInfo()fromperson并将其status连接到它。

@Override
String getInfo()
{
    return super.getInfo() + " " + getStatus(); // or jsut: + " " + status;
}
于 2013-09-19T21:10:45.537 回答