python - 将最高分写入数据文件

Question

我正在尝试创建一个仅包含一个数字的文件；我正在写的游戏的高分。

我有

f = open('hisc.txt', 'r+')

和

f.write(str(topScore))

我想知道该怎么做是：

• 擦除整个文件
• 获取文件中的数字并使其成为游戏中的变量
• 检查topScore是否高于文件中的数字，如果是则替换

Answer 1

擦除整个文件

with open('hisc.txt', 'w'):
    pass

获取文件中的数字并使其成为游戏中的变量

with open('hisc.txt', 'r') as f:
    highScore = int(f.readline())

检查topScore是否高于文件中的数字

if myScore > highScore:

如果是这样，更换它

if myScore > highScore:
    with open('hisc.txt', 'w') as f:
        f.write(str(myScore))

把它们放在一起：

# UNTESTED
def UpdateScoreFile(myScore):
    '''Write myScore in the record books, but only if I've earned it'''
    with open('hisc.txt', 'r') as f:
        highScore = int(f.readline())
    # RACE CONDITION! What if somebody else, with a higher score than ours
    # runs UpdateScoreFile() right now?
    if myScore > highScore:
        with open('hisc.txt', 'w') as f:
            f.write(str(myScore)) 

Answer 2

也许这是我的偏好，但我更习惯于在初始化时使用的习语，你做

f = open('hisc.txt','r')
# do some exception handling so if the file is empty, hiScore is 0 unless you wanted to start with a default higher than 0
hiScore = int(f.read())
f.close()

然后在游戏结束时：

if myScore > hiScore:
   f = open('hisc.txt', 'w')
   f.write(str(myScore))
   f.close()

Answer 3

f = open('hisc.txt', 'w')
f.write('10') # first score
f.close()


highscore = 25 #new highscore

# Open to read and try to parse
f = open('hisc.txt', 'r+')
try:
    high = int(f.read())
except:
    high = 0

# do the check
if highscore > high:
    high = highscore

f.close()

# open to erase and write again
f = open('hisc.txt', 'w')
f.write(str(high))
f.close()

# test
print open('hisc.txt').read()
# prints '25'