javascript -

Question

i have trouble with sorting an object in loop. when i do this code i get an Uncaught TypeError: Object # has no method 'sort' . why?) i googled this but doesn't found resolve

for (var i = 0; i < responseData.Airlines.length; i++) {

function sortPrice() {

    for (var s = 0; s < responseData.Airlines[i].FaresFull.length; s++) {
        responseData.Airlines[i].FaresFull[s].Pricing.ADTTotal = parseFloat(responseData.Airlines[i].FaresFull[s].Pricing.ADTTotal);

        responseData.Airlines[i].FaresFull[s].sort(function (a, b) {
            return parseFloat(a.Pricing.ADTTotal) > parseFloat(b.Pricing.ADTTotal);
        });

    }
}

sortPrice();

}

score 2 · Accepted Answer

排序方法仅在 Array 对象中可用。我猜您正在尝试对纯对象进行排序。

看：http ://www.w3schools.com/jsref/jsref_sort.asp他们在这里对数组进行排序

score 0 · Accepted Answer

排序是数组上的一个函数。您正在尝试对对象进行排序。试试这个：

function sortPrice() { 
    for (var i = 0; i < responseData.Airlines.length; i++) {
        for (var s = 0; s < responseData.Airlines[i].FaresFull.length; s++) {
            responseData.Airlines[i].FaresFull[s].Pricing.ADTTotal = 
                  parseFloat(responseData.Airlines[i].FaresFull[s].Pricing.ADTTotal);
        }
        responseData.Airlines[i].FaresFull.sort(function (a, b) {
            return parseFloat(a.Pricing.ADTTotal) - parseFloat(b.Pricing.ADTTotal);
        });
    }
}

您试图对每个元素调用排序，而不是对整个列表进行排序。我将排序从内部 for 循环中拉出来，并将比较器切换到 -1,0,1。

score 0 · Accepted Answer

由于您没有告诉我们您想做什么或您的数据看起来如何，我做了一个疯狂的猜测：

// move function header to top
function sortPrice(responseData) {
    for (var i = 0; i < responseData.Airlines.length; i++) {
//      dereference variables
        var airline = responseData.Airlines[i];
        for (var s = 0; s < airline.FaresFull.length; s++) {
            var pricing = airline.FaresFull[s].Pricing;
            pricing.ADTTotal = parseFloat(pricing.ADTTotal);
        }
//      move outside the loop
        airline.FaresFull .sort(function (a, b) {
//                       ^ no [s] - sort the array
//      don't do parseFloat another time
            return a.Pricing.ADTTotal - b.Pricing.ADTTotal;
        });
    }
}

sortPrice(yourData);

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