php - 连接 2 个数据库表获得总和值输出

Question

我将把它说得更清楚一点，因为我意识到它并不像应该的那样清楚。

表一

ID, COMPANY_ID, OPPORTUNITY, DATE_CREATE

表二

ID,ASSIGNED_BY_ID

我要做的是为每个 ASSIGNED_ID 添加 OPPORTUNITY 中的所有值。表一中的COMPANY_ID 与表二中的 ID 相同。

例如：

表一

COMPANY_ID | OPPORTUNITY | DATE_CREATE 
1000       | 50          | 2013/09/19
1000       | 100         | 2013/09/18
1000       | 200         | 2013/09/18
1005       | 100         | 2013/09/18
1005       | 200         | 2013/09/18

表二

ID         | ASSIGNED_BY_ID 
1000       | 4
1000       | 4
1000       | 4
1005       | 2
1005       | 2

所以我想要一个 SELECT 语句来提供这些结果：

ASSIGNED_BY_ID  | OPPORTUNITY
4               | 350
2               | 300

我想要每个 ASSIGNED_BY_ID 的单独选择语句。

这怎么可能？

Answer 1

尝试这个。

SELECT t1.ID,SUM(OPPORTUNITY) AS total 
FROM table1 t1
INNER JOIN table2 t2 ON t1.COMPANY_ID=t2.ID
WHERE t1.DATE_CREATE BETWEEN '$fromdate' AND '$todate' AND t2.ASSIGNED_BY_ID=1 
GROUP BY t1.ID

更新

SELECT t2.ASSIGNED_BY_ID,SUM(OPPORTUNITY) AS total 
FROM table1 t1
INNER JOIN table2 t2 ON t1.COMPANY_ID=t2.ID
WHERE t1.DATE_CREATE BETWEEN '$fromdate' AND '$todate' 
GROUP BY t2.ASSIGNED_BY_ID

Answer 2

请使用这个

   SELECT SUM(a.OPPORTUNITY) AS total, a.ID FROM table1 a inner join table2 b on a.COMPANY_ID =    b.ID  WHERE a.DATE_CREATE BETWEEN '$fromdate' AND '$todate' AND b.ASSIGNED_BY_ID=1 group by a.ID;