mysql - 如何选择重复项以获得正确的结果？

Question

你能帮我写一个有效的sql查询吗？

我需要选择所有重复的link_rewrite。仅当 id_shop、id_lang 相同时才重复。

查看完整代码：https ://github.com/Ha99y/prestashopCleanURLs/blob/master/PS15/cleanurls.php#L49

-------------------------------------------------------
| id_product  |  id_shop  |  id_lang  |  link_rewrite |
-------------------------------------------------------
|     1       |    1      |     1     |   ipod-nano   |
|     1       |    1      |     2     |   ipod-nano   |
|     2       |    1      |     1     |   ipod-nano   |
|     2       |    1      |     2     |   ipod-nano   |
|     8       |    2      |     1     |   ipod-nano   |
|     8       |    2      |     2     |   ipod-nano   |
-------------------------------------------------------

SQL：

SELECT * FROM `ps_product_lang`
WHERE `link_rewrite`
IN (SELECT `link_rewrite` FROM `ps_product_lang`
GROUP BY `link_rewrite`, `id_lang`
HAVING count(`link_rewrite`) > 1)

.

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Answer 1

在我看来，您的查询中唯一缺少的是id_shopfromGROUP BY子句。

SELECT * FROM `ps_product_lang`
WHERE `link_rewrite`
IN (SELECT `link_rewrite` FROM `ps_product_lang`
GROUP BY `link_rewrite`, `id_lang`, `id_shop`
HAVING COUNT(`link_rewrite`) > 1)

Answer 2

在 MySQL 中执行此操作的最有效方法是使用exists：

SELECT *
FROM `ps_product_lang` pl
WHERE exists (select 1 
              from `ps_product_lang` pl2
              where pl2.id_shop = pl.id_shop and
                    pl2.id_lang = pl.id_lang and
                    pl2.id_product <> pl.id_product
             );

Answer 3

您声明的要求是“仅当 id_shop、id_lang 相同时才重复”。这意味着，在某个地方，您的查询需要包含以下内容：

select id_shop, id_lang, count(*) records
from the applicable tables
group by id_shop, id_lang
having count(*) > 1

你只需要找到合适的位置来放置它。