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我正在为产品的位置定义一个案例，然后想稍后将该案例作为一个值返回。但是，我收到错误“'字段列表'中的未知列位置”。

SELECT location, avg(pcnt), max(pcnt), min(pcnt)
  FROM (
    -- create temporary table 'a' to serve data from inner typing table created below
    SELECT a.date_key, a.num_snowflakes/k.tot_snowflakes AS pcnt
      FROM (
        SELECT 
          date_key,
          CASE
            WHEN location_type_key=2 then 'at_customer' 
            WHEN location_type_key IN (1,13) then 'on_floor' 
            WHEN location_type_key IN (6,7,11) then 'sat1'
            WHEN location_type_key IN (4,5) then 'film'
            WHEN location_type_key IN (8,9) then 'repair'
            WHEN location_type_key IN (12) then 'inspection'
            WHEN location_type_key IN (2) then 'outside' 
            ELSE NULL END AS location,
          COUNT(distinct garment_key) AS num_snowflakes, 
          COUNT(distinct product_key) AS num_skus

          FROM database
          -- excluding vendor return and retired
            WHERE location_type_key NOT IN (3,10)
            -- between 6/15/13 and 8/15/13
              AND date_key >= 20130615 AND date_key <= 20130815
          -- aggregates by day and location case    
          GROUP BY date_key, location
        ) AS a
        JOIN 
        -- create temporary table 'k' to serve 'tot_snowflakes' to table 'a' above
          (SELECT b.date_key, sum(b.num_snowflakes) AS tot_snowflakes 
              FROM (
                SELECT 
                  date_key, 
                  CASE   
                    WHEN location_type_key=2 then 'at_customer' 
                    WHEN location_type_key IN (1,13) then 'on_floor' 
                    WHEN location_type_key IN (6,7,11) then 'sat1'
                    WHEN location_type_key IN (4,5) then 'film'
                    WHEN location_type_key IN (8,9) then 'repair'
                    WHEN location_type_key IN (12) then 'inspection'
                    WHEN location_type_key IN (2) then 'outside' 
                    ELSE NULL END AS location,
                  COUNT(distinct garment_key) AS num_snowflakes, 
                  COUNT(distinct product_key) AS num_skus

                  FROM database
                    WHERE location_type_key NOT IN (3,10)
                    -- between 6/15/13 and 8/15/13
                      AND date_key >= 20130615 AND date_key <= 20130815
                  -- aggregates by day and location case    
                  GROUP BY date_key, location
                ) AS b
            ) AS k
          ON a.date_key=k.date_key
      GROUP BY a.date_key, a.location
    ) AS z

我试图确保我总是调用正确的表，所以我不确定错误来自哪里。有人有想法么？

谢谢！

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1 回答 1

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您最外层的查询从表 z 中选择。

表 z 派生自 SELECT FROM 表 a JOIN 表 k。

表 a 派生自 SELECT FROM 表“数据库”。

表 k 派生自 SELECT FROM 派生表 b。

表 b 派生自 SELECT FROM 基表“数据库”。

这里的简短回答是，您查询的第一行实际上是在要求这个：

SELECT z.location, avg(z.pcnt), max(z.pcnt), min(z.pcnt)

派生表 z 只有两列，“date_key”和“pcnt”。

(SELECT a.date_key, a.num_snowflakes/k.tot_snowflakes AS pcnt
...
) AS z

为了使查询正常工作，表 z 需要一个位置，该位置在每个嵌套选择中都必须是显式的，直到您可以将其跟踪到您打算实际从中读取它的基表。

似乎该查询在其他方面为您尝试完成的结果所做的工作超出了必要的工作量，但我一直盯着它，直到我的眼睛失去了专注的能力，所以我会坚持这个答案时刻：需要将其“位置”列向上渗透到最外层选择的每个派生表都需要显式选择它。

于 2013-09-19T01:56:18.820 回答