我竭力想弄清楚为什么我的查询不起作用。这就是我的 search.php 页面的结果。我能够完美地 _GET 搜索词,但无法显示结果。
不确定问题是 fetch_array_assoc 还是什么!这是我的代码。对此的任何帮助将不胜感激。不是 100% 确定我的语法是否正确。
// Check connection
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$button = $_GET ['submit'];
$search = $_GET ['query'];
if (strlen($search) <= 1) {
echo "Search term too short";
}
else {
echo "You searched for <b>$search</b> <hr size='1'></br>";
$con = new mysqli("localhost", "user", "pass", "db");
// Check connection
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$search_exploded = explode(" ", $search);
foreach ($search_exploded as $search_each) {
$x++;
if ($x == 1) {
$query = "Keyword_ID LIKE '%$search_each%' or Keyword_Name LIKE '%$search_each%' ";
}
else {
$query .= "OR Keyword_ID LIKE '%$search_each%' or Keyword_Name LIKE '%$search_each%' ";
}
}
$construct = mysqli_query($con, "SELECT * FROM profileTable WHERE $query");
$construct = mysqli_query($con, "SELECT * FROM addKeywordTable (Keyword_Name) WHERE $query");
$constructs = mysqli_multi_query($construct);
if (mysqli_multi_query($construct)) {
$numrows = mysqli_num_rows($query);
if ($numrows > 0) {
while ($row = mysqli_fetch_assoc($constructs)) {
$key = $row['Keyword_Name'];
$keyID = $row['keyID'];
$fname = $row['FirName'];
$lname = $row['LaName'];
$mname = $row['MName'];
$suffix = $row['Suffix'];
$title = $row['Title'];
$dept = $row['Dept'];
$phone1 = $row['PH1'];
$phone2 = $row['PH2'];
$email = $row['Email'];
$photo = $row['Photo'];
$bio = $row['BioLK'];
$tags = $row['Tags'];
echo '<h2>$fname $lname</h2>';
echo $key;
echo $title;
echo $dept;
}
}
else {
echo "Results found: \"<b>$x</b>\"";
}
}
}
mysqli_close();
?>
我正在尝试搜索两个不同的表。addKeywordTable 和 profileTable。配置文件表包含用户的所有配置文件信息。addKeywordTable 存储关键字/标签名称“Keyword_Name”。
我试图创建一个 mysqli_multi_query 但它根本不起作用。