1

CakePHP 2.4

添加新用户时,我必须先对密码进行哈希处理,然后再将其存储到数据库中。为此,我做了:

//UsersController
public $helpers = array('Html', 'Form');
public $components = array(
    'Session',
    'Auth' => array(
    'loginRedirect' => array('controller' => 'users', 'action' => 'home', 'home'),
    'logoutRedirect' => array('controller' => 'users', 'action' => 'logout')
    )
);
public function add(){
    if($this->request->is('post')){
        $this->User->create();
        if($this->User->save($this->request->data)){
            $this->Session->setFlash('Saved!');
        }
    }
}

//UserModel
public function beforeSave(){
    if(isset($this->data[$this->alias]['password']))
        $this->data[$this->alias]['password'] = md5($this->data[$this->alias]['password']);
    return true;
}

//add.ctp
echo $this->Form->create();
echo $this->Form->input('text', array('label'=>'Username', 'name'=>'username'));
echo $this->Form->input('text', array('label'=>'Full name', 'name'=>'fullname'));
echo $this->Form->input('password', array('label'=>'Password', 'name'=>'password'));
echo $this->Form->input('text', array('label'=>'Password hint', 'name'=>'pass_hint'));
echo $this->Form->input('text', array('label'=>'Email', 'name'=>'email'));
echo $this->Form->input('text', array('label'=>'Contact', 'name'=>'cell'));
echo $this->Form->end('Create account');

但问题是密码在没有经过哈希处理的情况下被存储!

提前致谢...

更新:将视图代码更改为

echo $this->Form->create('User');
echo $this->Form->input('username', array('label'=>'Username'));
echo $this->Form->input('fullname', array('label'=>'Full name'));
echo $this->Form->input('pwd', array('label'=>'Password', 'type'=>'password'));
echo $this->Form->input('pass_hint', array('label'=>'Password hint'));
echo $this->Form->input('email', array('label'=>'Email'));
echo $this->Form->input('cell', array('label'=>'Contact'));
echo $this->Form->end('Create account');
4

3 回答 3

2

我不知道为什么,但我刚刚用用户表烘焙了一个项目,发现 CakePHP 2.4 将模型命名为User而不是UserModel. 所以,我将我的改名为UserModeltoUser并且神奇地为我工作:)

于 2013-09-18T16:37:41.460 回答
0

您正在通过在输入类型中设置名称属性来更改默认行为,

删除名称属性然后它会工作,

在您的用户模型 beforesave 功能中,您正在检查

if(isset($this->data[$this->alias]['password']))

由于您正在设置这样的密码,因此不再存在

echo $this->Form->input('password', array('label'=>'Password', 'name'=>'password'));

将其更改为

echo $this->Form->input('User.password', array('label'=>'Password'));

更新

并且像这样更新表格然后它会完美地工作。

echo $this->Form->create('User');
echo $this->Form->input('username', array('label'=>'Username'));
echo $this->Form->input('fullname', array('label'=>'Full name'));
echo $this->Form->input('password', array('label'=>'Password', 'name'=>'password'));
echo $this->Form->input('pass_hint', array('label'=>'Password hint'));
echo $this->Form->input('email', array('label'=>'Email'));
echo $this->Form->input('cell', array('label'=>'Contact'));
echo $this->Form->end('Create account');
于 2013-09-18T06:31:38.370 回答
0

您忘记了添加操作的重要部分:

public function add(){
    if ($this->request->is('post')){
        $this->User->create(); // important!
        if ($this->User->save($this->request->data)){
            $this->Session->setFlash('Saved!');
        }
    }
}

它可能适用于您的情况(有时),但是一旦您在 beforeFilter() 回调等中执行某事,它就很容易中断

于 2013-09-18T17:22:14.387 回答